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kari74 [83]
3 years ago
7

What is the range of the function h(x) = -8x?

Mathematics
1 answer:
Blababa [14]3 years ago
4 0
You switch h(x) with y and get y= -8x. You aren't given a range, as the range is the y-intercpet.
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James joins Club One which charges a monthly membershi[ of $ 19.99. How much will James spend in all, if he continues his member
maria [59]

Answer:

James will spend $119.94

Step-by-step explanation:

Multiply $19.99 by 6.

<em>$19.99 x 6 = $119.94</em>

8 0
3 years ago
A grapefruit is 8% heavier than an orange, and an apple is 10% lighter than the orange.
likoan [24]
Weight of an grapefruit=weight of an orange+8% weight of an orange
weight of an apple=weight of an orange -10% weight of an orange

a.<span>By what percentage is the grapefruit heavier than the apple?
We should find the connection between grapefruit and an apple. We know the connection between the weight of a grapefruit and an orange, we know the connection between an orange and an apple, so this means we know the connection between a grapefruit and an apple.
</span>
weight of an grapefruit=weight of an <span>orange+8% weight of an orange
</span>weight of an orange=weight of an apple<span> +10% weight of an apple
</span>
-> weight of an grapefruit=weight of an apple+10% weight of an apple + 8%(weight of an apple+10% weight of an apple)= weight of an apple + 18% weight of an apple + 2% weight of an apple= <span>weight of an apple + 20% weight of an apple 

</span><span>b.By what percentage is the apple lighter than the grapefruit?
</span>weight of an grapefruit=weight of an apple + 20% weight of an apple<span> 
</span>
-> The apple ts 20% lighter than the grapefruit.
8 0
3 years ago
Read 2 more answers
I need help solving it
Oxana [17]
7. the last one

I = P R T

I = 15.75 P = 500 R = unknown T = 6

15.75 = 500 (r) (6)

divide the T and I

15.75 ÷ 6 = 500 (r) (6) ÷6

2.62 = 500 (r) *get rid of the six*

divide the P with new answer

2.62 ÷ 500 = 500 ÷ 500 *get rid of 500*

0.00524 = r

move decimal to make it in to a percentage

5.24% = R






6 0
3 years ago
How do I find this help please
KIM [24]
Area of the sector = 1/2 * r^2 * theta where theta is the angle subtended by the arc at the center  ( in radians)

In this case m < theta = 360 - 235 = 125 degrees or  2.182 radians

So, the area of shaded area = 1/2 * 20^2 * 2.182 =   436.4 in^2
8 0
4 years ago
Select "Growth" or "Decay" to classify each function.
allochka39001 [22]

1. The growth rate equation has a general form of:

y = A (r)^t

The function is growth when r≥1, and it is a decay when r<1. Therefore:

y=200(0.5)^2t                    --> Decay

y=1/2(2.5)^t/6                  --> Growth

y=(0.65)^t/4                       --> Decay

 

2. We rewrite the given equation (1/3)^d−5 = 81

 

Take the log of both sides:

(d – 5) log(1/3) = log 81

d – 5 = log 81 / log(1/3)

d – 5 = - 4

 

Multiply both sides by negative 1:

- d + 5 = 4

So the answer is D

5 0
3 years ago
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