Answer: The required equations of hyperbolas would be
![49x^2-98x-64y^2+256y-2831=0\\\\4x^2+32x-25y^2-250y+589=0\\\\81x^2+512x-64y^2-324y-3836=0](https://tex.z-dn.net/?f=49x%5E2-98x-64y%5E2%2B256y-2831%3D0%5C%5C%5C%5C4x%5E2%2B32x-25y%5E2-250y%2B589%3D0%5C%5C%5C%5C81x%5E2%2B512x-64y%5E2-324y-3836%3D0)
Step-by-step explanation:
Since we know that
The general equation for a conic section:
![Ax^2+Bxy+Cy^2+Dx+Ey+F=0](https://tex.z-dn.net/?f=Ax%5E2%2BBxy%2BCy%5E2%2BDx%2BEy%2BF%3D0)
In case of hyperbola, we get that
![Discriminant=B^2-4AC>0](https://tex.z-dn.net/?f=Discriminant%3DB%5E2-4AC%3E0)
According to this, both x and y are squared.
And one of the coefficient of x and y must be positive and one of the coefficient of x and y must be negative.
So, the required equations of hyperbolas would be
![49x^2-98x-64y^2+256y-2831=0\\\\4x^2+32x-25y^2-250y+589=0\\\\81x^2+512x-64y^2-324y-3836=0](https://tex.z-dn.net/?f=49x%5E2-98x-64y%5E2%2B256y-2831%3D0%5C%5C%5C%5C4x%5E2%2B32x-25y%5E2-250y%2B589%3D0%5C%5C%5C%5C81x%5E2%2B512x-64y%5E2-324y-3836%3D0)