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ludmilkaskok [199]
3 years ago
15

HELP Which equations represent hyperbolas?

Mathematics
2 answers:
MissTica3 years ago
7 0
An elliptical equation is in the form
Ax^2+Bx+Cy^2+Dy+E=0
the equation is a Hyperbola. When x and y are both squared, and exactly one of the coefficients is negative and exactly one of the coefficients is positive.
1-49x^2-98x-64y^2+256y-2831=0
2-4x^2+32x-25y^2-250y+589=0
3-81x^2+512x-64y^2-324y-3836=0
Hoochie [10]3 years ago
5 0

Answer: The required equations of hyperbolas would be

49x^2-98x-64y^2+256y-2831=0\\\\4x^2+32x-25y^2-250y+589=0\\\\81x^2+512x-64y^2-324y-3836=0

Step-by-step explanation:

Since we know that

The general equation for a conic section:

Ax^2+Bxy+Cy^2+Dx+Ey+F=0

In case of hyperbola, we get that

Discriminant=B^2-4AC>0

According to this, both x and y are squared.

And one of the coefficient of x and y must be positive and one of the coefficient of x and y must be negative.

So, the required equations of hyperbolas would be

49x^2-98x-64y^2+256y-2831=0\\\\4x^2+32x-25y^2-250y+589=0\\\\81x^2+512x-64y^2-324y-3836=0

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Fudgin [204]
It’s going to be 6 units
7 0
2 years ago
An open box with a square base is to have a volume of 18 ft^3.
kotegsom [21]

Answer:

2.29 ft of side length and 1.14 height

Step-by-step explanation:

a) Volume V = x2h, where x is side of square base and h is hite.

Then surface area S = x2 + 4xh because box is open.

b) From V = x2h = 6 we have h = 6/x2.

Substitude in formula for surface area: S = x2 + 4x·6/x2, S = x2 + 24/x.

We get S as function of one variable x. To get minimum we have to find derivative S' = 2x - 24/x2 = 0, from here 2x3 - 24 = 0, x3 = 12, x = (12)1/3 ≅ 2.29 ft.

Then h = 6/(12)2/3 = (12)1/3/2 ≅ 1.14 ft.

To prove that we have minimum let get second derivative: S'' = 2 + 48/x3, S''(121/3) = 2 + 48/12 = 6 > 0.

And because by second derivative test we have minimum: Smin = (12)2/3 + 4(12)1/3(12)1/3/2 = 3(12)2/3 ≅ 15.72 ft2

5 0
2 years ago
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nlexa [21]

Answer:

-1/3

Step-by-step explanation:

Taking two points on the graph (I took (0,9) and (6,7)

Slope=(y2-y1)/(x2-x1)

(7-9)/(6-0)=-2/6

=-1/3

7 0
3 years ago
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Answer:

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Step-by-step explanation:

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