Google will help you with this
Elastic collisions meant that there will be no change in the total momentum of the system and surrounding after collision.
<u>Explanation:</u>
Collision is the process where two or more bodies hit each other. So when they hit each other, transfer of energy will be occurring between them. In other words, the momentum can be changed after the collision. There are two kinds of collision.
- elastic collision
- inelastic collision
The elastic collision are those which will not undergo any change in the total momentum after collision. This means that the sum of momentum of the objects before collision will be equal to the sum of momentum of the objects after collision. Thus, there will be no change in the total momentum of the object after collision in case of elastic collision.
The equilibrium constant, k of the reaction in which case, the concentrations of the given reactants and products are as indicated is; Choice A; K = 3.1 x 10⁵
<h3>What is the equilibrium constant , k of the reaction as described in the task content?</h3>
It follows from above that the concentrations of the reactants and products are as follows; [H2] = 0.10 M, [N2] = 0.10 M, and [NH3] = 5.6 M at equilibrium.
Hence, the equilibrium constant of the reaction in discuss is;
K = [5.6]²/[0.10]³[0.10]
k = 5.6² × 10⁴
k = 3.136 × 10⁵
K = 3.1 × 10⁵.
Read more on equilibrium constant;
brainly.com/question/1619133
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Answer:
I think
Explanation:
Li = 2s^1
Be = 2s^2
B = 2p^1
C = 2p^2
I think that is what it is asking if not sorry
Answer:
this really works https://chem.libretexts.org/Courses/Saint_Marys_College_Notre_Dame_IN/CHEM_122-02_(Under_Construction)/1%3A_Review_from_CHEM_121/1.05%3A_Units%2C_Measurement_Uncertainty%2C_and_Significant_Figures_(Worksheet)
