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just olya [345]
3 years ago
13

What is the percent by mass of water in Na2SO4 • 10H2O?

Chemistry
1 answer:
netineya [11]3 years ago
6 0
Your answer is 55.92%
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Match the prefix with the power of ten it represents.
Sunny_sXe [5.5K]

kilo 103 is the correct answer so it would mostly be 2

6 0
3 years ago
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What is the electron configuration of oxygen?​
baherus [9]

Answer:

Electron configuration: [He] 2s²2p⁴

Explanation:

5 0
3 years ago
The change in enthalpy is the change in heat energy of a reaction and is calculated by (Hint: Hess' Law): Group of answer choice
Stolb23 [73]

Answer:

d. Sum of product enthalpies minus the sum of reactant enthalpies

Explanation:

The standard enthalpy change of a reaction (ΔH°rxn) can be calculated using the following expression:

ΔH°rxn = ∑n(products) × ΔH°f(products) - ∑n(reactants) × ΔH°f(reactants)

where,

ni are the moles of products and reactants

ΔH°f(i) are the standard enthalpies of formation of products and reactants

8 0
3 years ago
The pKa of lactic acid is 3.9. A lactate buffer will be useful from pH values ________. The pKa of lactic acid is 3.9. A lactate
Vedmedyk [2.9K]

Answer:

Explanation:

The usefulness of a buffer is its ability to resist changes in pH when small quantities of base or acid are added to it. This ability is the consequence of having both the conjugate base and the weak acid present in solution which will consume the added base or acid.  

This capacity is lost if the ratio of the concentration of conjugate base to the concentration of weak acid differ by an order of magnitude. Since  buffers having ratios differing by more will have their pH driven by either the weak acid or its conjugate base .

From the Henderson-Hasselbach equation we have that

pH = pKa + log [A⁻]/[HA]

thus

0.1 ≤  [A⁻]/[HA] ≤ 10

Therefore the log of this range is -1 to 1, and the pH will have a useful range of within +/- 1 the pKa of the buffer.

Now we are equipped to answer our question:

pH range = 3.9 +/- 1 = 2.9 through 4.9

7 0
3 years ago
Find the density of a material given that a 5.03g sample occupies 3.24ml
Verizon [17]

Formula for density:

D = Mass / Volume

Mass = 5.03g

Volume = 3.24ml


Formula in our case:

D = 5.03 / 3.24

D = 0.31~g/m^{3}


Hope it helped,


BioTeacher101

3 0
3 years ago
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