i need help ls i thank its book 500 grams
Answer:
The new pressure will be 0.225 kPa.
Explanation:
Applying combined gas law:

where,
are initial pressure and volume at initial temperature
.
are final pressure and volume at initial temperature
.
We are given:



Putting values in above equation, we get:


Hence, the new pressure will be 0.225 kPa.
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Answer: The three main rock types are igneous, metamorphic and sedimentary.
The three processes that change one rock to another are crystallization, metamorphism, and erosion and sedimentation.
Any rock can transform into any other rock by passing through one or more of these processes. This creates the rock cycle.
Explanation:
Answer:

Explanation:
Hello!
In this case, according to the chemical reaction:

We can evidence the 2:1 mole ratio between hydrogen and tin, thus, we perform the following stoichiometric setup to obtain the mass of produced tin:

Best regards!