Answer:- 0.456 L
Solution:- Looking at the given information, only volume and pressure are changing and the temperature is constant. We know that, at constant temperature, the volume of the gas is inversely proportional to the pressure.
![P_1V_1=P_2V_2](https://tex.z-dn.net/?f=P_1V_1%3DP_2V_2)
= 735 torr
= 807 torr
= 500. mL
= ?
Let's plug in the values in the equation and solve it for final volume.
![735torr(500.mL)=807torr(V_2)](https://tex.z-dn.net/?f=735torr%28500.mL%29%3D807torr%28V_2%29)
![V_2=\frac{735torr(500.mL)}{807torr}](https://tex.z-dn.net/?f=V_2%3D%5Cfrac%7B735torr%28500.mL%29%7D%7B807torr%7D)
![V_2=456mL](https://tex.z-dn.net/?f=V_2%3D456mL)
since, 1 L = 1000 mL
![456mL(\frac{1L}{1000mL})](https://tex.z-dn.net/?f=456mL%28%5Cfrac%7B1L%7D%7B1000mL%7D%29)
= 0.456 L
So, the volume of carbon dioxide at the new pressure will be 456 mL or 0.456 L.
I have no idea i am so sorry
Answer:
31,380 Joules
Explanation:
Given Data:
Mass = m = 100 g
Temperature 1 = = 25 °C
Temperature 2 = = 100 °C
Specific Heat Constant = c = 4.184
Change in Temp. = ΔT = 100 - 25 = 75 °C
Required:
Heat = Q = ?
Formula:
Q = mcΔT
Solution:
Q = (100)(4.184)(75)
Q = 31, 380 Joules
Hope this helped!
~AH1807
When a sample of a gas is heated in a sealed, rigid
container from 200 degree Kelvin to 400 degree Kelvin, the pressure exerted by
the gas is increased by a factor 2. Heating any gas actually increases the
volume of the gas within a container. As the temperature of the gas rises, the
molecules of the gas start moving faster and start striking the walls of the
container in which it is kept with more force. The volume of the container
tries to expand to accommodate the fast colliding molecules of the gas.
Answer:
17.03052 g/mol
Explanation:
Ammonia formula is given as NH3.
To estimate the molar mass of any compound, we have to add up the molar masses of every atom of the given compound. Ammonia comprises of one nitrogen atom and three hydrogen atoms.
So the molar mass of ammonia is
N: 14.0067 g/mol
H: 1.00794 g/mol
The molar mass of ammonia will thus be
14.0067 g/mol +3× 1.00794 g/mol =17.03052 g/mol