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3 years ago

Please give me the answer to 8p+5=77?

Mathematics

2 answers:

vitfil [10]3 years ago

8 0

8p+5=77
-5=-5
8p=72
dived by 8 on both sides
p=9

denis23 [38]3 years ago

6 0

The answer is P=9
because to isolate the variable subtract 5 from both sides then divide 72 by 8 to get 9

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Sandy builds this shape of four

omeli [17]

Answer:

Triangular Pyramid

30.5 cm^3 (cubic centimeters)

Step-by-step explanation:

a shape made up of four triangles is a triangular pyramid.

Volume of any pyramid is (1/3)*Area of the base*height.

area of the base, or any face, is 17.6 as said in the question, now the height. is 5.2 so we can solve then.

V = 1/3 * 17.6 * 5.2 = 30.5

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2 years ago

Find the value of x in the triangle shown below. X = 44° xo 29°

densk [106]

Answer:

x = 107°

Step-by-step explanation:

The sum of all 3 angles in any triangle needs to equal 180°.

This means that 44° + 29° + x = 180°

180° - 44° - 29° = 107°

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1 year ago

Simplify (9s/2t)* (2s/3)

ehidna [41]

Answer:

You'd get 18s^2/6t by simply multiplying. To simplify just decide each sides by 6 and you'd get 3s^2/t

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

If f(x, y, z) = x sin(yz), (a) find the gradient of f and (b) find the directional derivative of f at (2, 4, 0) in the direction

valentina_108 [34]

Answer:

a) $\nabla f(x,y,z) = \sin{yz}\mathbf{i} + xz\cos{yz}\mathbf{j} + xy \cos{yz}\mathbf{k}$ .

b) $Du_{f}(2,4,0) = -\frac{8}{\sqrt{11}}$

Step-by-step explanation:

Given a function $f(x,y,z)$ , this function has the following gradient:

$\nabla f(x,y,z) = f_{x}(x,y,z)\mathbf{i} + f_{y}(x,y,z)\mathbf{j} + f_{z}(x,y,z)\mathbf{k}$ .

(a) find the gradient of f

We have that $f(x,y,z) = x\sin{yz}$ . So

$f_{x}(x,y,z) = \sin{yz}$

$f_{y}(x,y,z) = xz\cos{yz}$

$f_{z}(x,y,z) = xy \cos{yz}$ .

$\nabla f(x,y,z) = f_{x}(x,y,z)\mathbf{i} + f_{y}(x,y,z)\mathbf{j} + f_{z}(x,y,z)\mathbf{k}$ .

$\nabla f(x,y,z) = \sin{yz}\mathbf{i} + xz\cos{yz}\mathbf{j} + xy \cos{yz}\mathbf{k}$

(b) find the directional derivative of f at (2, 4, 0) in the direction of v = i + 3j − k.

The directional derivate is the scalar product between the gradient at (2,4,0) and the unit vector of v.

We have that:

$\nabla f(x,y,z) = \sin{yz}\mathbf{i} + xz\cos{yz}\mathbf{j} + xy \cos{yz}\mathbf{k}$

$\nabla f(2,4,0) = \sin{0}\mathbf{i} + 0\cos{0}\mathbf{j} + 8 \cos{0}\mathbf{k}$ .

$\nabla f(2,4,0) = 0i+0j+8k=(0,0,8)$

The vector is $v = i + 3j - k = (1,3,-1)$

To use v as an unitary vector, we divide each component of v by the norm of v.

$|v| = \sqrt{1^{2} + 3^{2} + (-1)^{2}} = \sqrt{11}$

$v_{u} = (\frac{1}{\sqrt{11}}, \frac{3}{\sqrt{11}}, \frac{-1}{\sqrt{11}})$

Now, we can calculate the scalar product that is the directional derivative.

$Du_{f}(2,4,0) = (0,0,8).(\frac{1}{\sqrt{11}}, \frac{3}{\sqrt{11}}, \frac{-1}{\sqrt{11}}) = -\frac{8}{\sqrt{11}}$

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3 years ago

Tell if the slope is positive, negative, zero, or no slope. POSITIVE

dolphi86 [110]

Answer:

Negative

Step-by-step explanation:

The line is trending downwards, which is indicative of a negative slope.

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3 years ago