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barxatty [35]
4 years ago
5

A frequency generator sends a 550 Hz sound wave through both water and ice.

Physics
2 answers:
Brums [2.3K]4 years ago
3 0

Δλ =  3.103 m.

To solve this problem we have to know the speed of sound in both elements water and ice.

Element            Speed of sound

Water (25°C)           1493 m/s

Ice                           3200 m/s

The velocity of a wave is given by the equation v = λf, where λ is the wavelength, and f is the frecuency of the wave.

In order to calculate the wavelength we have to clear λ in the equation v = λf, resulting:

λ = v/f

Calculating the wavelength in both elements:

λ(water) = 1493 m/s / 550 Hz = 2.715 m

λ(ice) = 3200 m/s / 550 Hz = 5.818 m

So, the difference in wavelength between the wave produced in ice and the wave produced in water is:

Δλ = λ(water) - λ(ice) = 5.818 m - 2.715 m

Δλ =  3.103 m

Ghella [55]4 years ago
3 0

Answer:

3.1 m

Explanation:

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V_{f}=0-(9.8 m/s^{2})(10.30 s)  (7)

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