Answer:
The radius of the slave piston = 14.10 cm
Explanation:
The formula to apply here is that for pressure where ;
Pressure = Force / Area
F₁ /A₁ =F₂/A₂ where ; F₁=200 N , A₁= 25 cm² , F₂ =5000 N ,A₂ =?
Apply values in the equation as ;
200/ 25 = 5000/ A₂
A₂ = 625 cm²
Formula for area is ;
A = πr²
625 = π * r²
625/π = r²
√625/π =r
14.10 cm = r
When a liquid is cooled,the kinetic energy of the particles <u>decreases</u>. The force of attraction between the particles <u>increases</u>, the space between the particles <u>decreases</u>.
Explanation:
It is given that,
Density of asteroid, ![\rho=4000\ kg/m^3](https://tex.z-dn.net/?f=%5Crho%3D4000%5C%20kg%2Fm%5E3)
Mass of asteroid, ![m=10^{17}\ kg](https://tex.z-dn.net/?f=m%3D10%5E%7B17%7D%5C%20kg)
We need to find the diameter of the asteroid. The formula of density is given by:
![\rho=\dfrac{m}{V}](https://tex.z-dn.net/?f=%5Crho%3D%5Cdfrac%7Bm%7D%7BV%7D)
V is the volume of spherical shaped asteroid, ![V=\dfrac{4}{3}\pi r^3](https://tex.z-dn.net/?f=V%3D%5Cdfrac%7B4%7D%7B3%7D%5Cpi%20r%5E3)
![r^3=\dfrac{3M}{4\pi \rho}](https://tex.z-dn.net/?f=r%5E3%3D%5Cdfrac%7B3M%7D%7B4%5Cpi%20%5Crho%7D)
![r^3=\dfrac{3\times 10^{17}\ kg}{4\pi \times 4000\ kg/m^3}](https://tex.z-dn.net/?f=r%5E3%3D%5Cdfrac%7B3%5Ctimes%2010%5E%7B17%7D%5C%20kg%7D%7B4%5Cpi%20%5Ctimes%204000%5C%20kg%2Fm%5E3%7D)
![r^3=\sqrt{5.96\times 10^{12}}](https://tex.z-dn.net/?f=r%5E3%3D%5Csqrt%7B5.96%5Ctimes%2010%5E%7B12%7D%7D)
r = 2441311.12 m
Diameter = 2 × radius
d = 4882622.24 m
or
![d=4.88\times 10^6\ m](https://tex.z-dn.net/?f=d%3D4.88%5Ctimes%2010%5E6%5C%20m)
Hence, this is the required solution.
-10/3m/s2. The formula for acceleration is (Final speed - initial speed)/ time.
Thus, (0m/s - 10m/s)/3s is 10m/s/3s which then can be simplified to /10/3m/s2
The correct answer is picture 1 because the grey arrow represents the real object size and the orange - yellowish arrow represents the image size. So since the image size is bigger than the object size. So this means picture 1 has a larger image.