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stepan [7]
3 years ago
10

What is the temperature of air if the speed of sound is 295m/s?​

Physics
1 answer:
victus00 [196]3 years ago
7 0

Answer:

Explanation:The speed of sound depends on several variables, but the only independent variable we need to calculate the speed of sound ... Enter your air temp and choose your units: The speed of sound: mph. Fahrenheit, knots. Celsius, m/s. Kelvin, ft/s.

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A rock tied to the end of a string moves in a circle at a constant speed of 2.5 m/s and experiences an acceleration of 4.0 m/s.
artcher [175]

The radius of the circular motion at the given speed is 1.56 m.

The given parameters;

  • <em>speed of the rock, v = 2.5 m/s</em>
  • <em>acceleration of the rock, a = 4 m/s²</em>

<em />

The radius of the circular motion is calculated by using centripetal acceleration formula as follows;

a_c = \frac{v^2}{r} \\\\r = \frac{v^2}{a_c} \\\\r = \frac{2.5^2}{4} \\\\r = 1.56 \ m

Thus, the radius of the circular motion at the given speed is 1.56 m.

Learn more about centripetal acceleration here: brainly.com/question/79801

8 0
2 years ago
A 23.3 kg crate is pushed with a force of 944 N for 36.0 seconds, moving the crate a distance of 12.4 m. How much power was used
tigry1 [53]

Explanation:

p  =  \frac{f \times s}{t}

power = Force × distance /time

power = 944N × 12.4m/36secs

power = (944×12.4/36)Nms—¹

power = 390.2Nms—¹ or 390.2Watts or 390.2Js—¹

8 0
3 years ago
I'm not sure about these 2 questions
Natali [406]
2) Newton's third law<span>: For every action, there is an equal and opposite reaction.

3) Please provide the diagram </span>
7 0
4 years ago
A wave has a wavelength of 0.5 m and a frequency of 5.0 Hz. What is the speed of the wave?
mylen [45]
The correct option is (A) 2.5 m/s

Explanation:
Since,

v = fλ ---- (1)

where v = speed of the wave
f = frequency of the wave = 5 Hz
λ = wavelength of the wave = 0.5 

Plug in the value in (1):
(1) => v = 5 * 0.5
v = 2.5 m/s
7 0
3 years ago
Read 2 more answers
A hummingbird flies 2.0 m along a straight path at a height of 5.3 m above the ground. Upon spotting a flower below, the humming
stepan [7]

To solve this problem we will apply the concepts of Pythagoras to find the net path. An easy way is to graph the path to trace the path, which resembles that of a right triangle. The information provided is equivalent to that of the two short sides of the triangle, so we will find the longest side by the Pythagorean theorem. In this way,

OC = \sqrt{2^2+2.4^2}

OC = 3.12m

Therefore the magnitude of the hummingbird’s total displacement is 3.12m

6 0
4 years ago
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