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jolli1 [7]
3 years ago
15

Suppose you weigh 658 N, and when you stand on one foot, your weight is spread out over an area of 1.130×10-2 m2. What pressure

does your foot exert on the floor? (Check out the book or online for the correct unit. Remember that there is also a blue help button if the units are inconsistent.
Physics
1 answer:
podryga [215]3 years ago
5 0

Answer:

58230.08849 Pa

Explanation:

F = W = Weight of the person = 658 N

A = Area to which the force is applied = 1.13\times 10^{-2}\ m^2

When the force is divided by the area to which the force is applied we obtain the pressure

P=\frac{F}{A}\\\Rightarrow P=\frac{658}{1.13\times 10^{-2}}\\\Rightarrow P=58230.08849\ N/m^2=58230.08849\ Pa

Hence, pressure the foot exerts on the floor is 58230.08849 Pa

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