Use "PEMDAS"
First we'll add then subtract
24/4=6
so 6 pieces on each side, since a rectangle is a square
Answer:
The correct answer is;
No, the quadrilateral is not always a parallelogram
Step-by-step explanation:
Since there are only four opposite angles in a quadrilateral there are only two possible angle bisectors of the opposite angles also, the angle bisectors of a pair of opposite angles of a quadrilateral will intersect within the quadrilateral and therefore they cannot form the sides of a parallelogram
Therefore, the answer is no, the quadrilateral is not always a parallelogram.
Answer:
Step-by-step explanation:
Consider the given expression is
![\ln (x\sqrt[3]{x^2+1})](https://tex.z-dn.net/?f=%5Cln%20%28x%5Csqrt%5B3%5D%7Bx%5E2%2B1%7D%29)
We need to rewrite the expression as a sum,difference,or multiple of logarithms.
![[\because \sqrt[n]{x}=x^{\frac{1}{n}}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Csqrt%5Bn%5D%7Bx%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D%5D)
Using the properties of logarithm we get
![[\because \ln (ab)=\ln a+\ln b]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Cln%20%28ab%29%3D%5Cln%20a%2B%5Cln%20b%5D)
![[\because \ln (a^b)=b\ln a]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Cln%20%28a%5Eb%29%3Db%5Cln%20a%5D)
Therefore, the simplified form of the given expression is .
4/7 - x = 6/35
You're trying to get x by itself, so you have to subtract 4/7 from both sides.
-x = 6/35 - 4/7
You need both of the fractions to the right of the equal sign to have the same denominator so that we could simplify them, so multiply 5/5 to -4/7.
-4 /7 × 5/5 = -20/35
So, our new equation is :
-x = 6/35 - 20/35
Simplify.
-x = -14/35
Divide both sides by -1.
x = 14/35
Divide by 7.
x = 2/5
~Hope I helped!~
