If you are talking about evolution, the two types of evidence is
1. fossil evidence
2. molecular evidence
I belive the answer is all of the above
I thinking the answer was for some genes, both alleles express together. Others combine to give an average phenotype....
<span>In Drosophila + indicates wild-type allele for any gene, m is mahogany and e is ebony.
Female parents are m+/m+ and males are +e/+e.
F1 are m+/+e, all wild type. F1 females are crossed with me/me males - the test cross.
Offspring will be : non recombinant m+/me, mahogany wild type or +e/me wild type ebony. OR
recombinant me/me mahogany ebony or ++/++ wild type.
As the two genes are 25 map units apart, the percentage of recombinants will be 25% and therefore percentage parental types will be 75%.
75% 1000 is 750. There are two parental types, so you would expect 375 of each. Therefore, you would expect 375 m+/me and 375 +e/me.
25% of 1000 is 250 split between two recombinants =125 of each. Therefore you would expect 135 me/me and 125 ++/++</span>
The hydrolysis of pyrophosphate from the approaching UTP atom. The term pyrophosphate is additionally the name of esters framed by the buildup of a phosphorylated organic compound with inorganic phosphate, concerning dimethylallyl pyrophosphate. This bond is likewise alluded to as a high-vitality phosphate bond.
