Answer:
The probability that there are 3 or less errors in 100 pages is 0.648.
Step-by-step explanation:
In the information supplied in the question it is mentioned that the errors in a textbook follow a Poisson distribution.
For the given Poisson distribution the mean is p = 0.03 errors per page.
We have to find the probability that there are three or less errors in n = 100 pages.
Let us denote the number of errors in the book by the variable x.
Since there are on an average 0.03 errors per page we can say that
the expected value is, 
= E(x)
= n × p
= 100 × 0.03
= 3
Therefore the we find the probability that there are 3 or less errors on the page as
P( X ≤ 3) = P(X = 0) + P(X = 1) + P(X=2) + P(X=3)
Using the formula for Poisson distribution for P(x = X ) = 
Therefore P( X ≤ 3) = 
= 0.05 + 0.15 + 0.224 + 0.224
= 0.648
The probability that there are 3 or less errors in 100 pages is 0.648.
Answer:
555
Step-by-step explanation:
Answer:
Step-by-step explanation:
she will earn 12 dollars a year i think
Answer:
What is the question?
Step-by-step explanation:
Answer:
Part 1) Is not a valid code
Part 2) The last digit should be 6 in order to make it a valid code
Step-by-step explanation:
we have
2-81273-05213-8
we know that
The last number is the check digit (8)
<em>Verify the UPC number</em>
step 1
Sum the digits in the odd positions, starting at the left
so
2+1+7+0+2+3=15
step 2
Multiply the answer in step 1 by 3
15(3)=45
step 3
Sum the numbers in the even positions, ignoring the last (12th) digit because that is the check digit that you are verifying
Do not multiply this number by 3.
8+2+3+5+1=19
step 4
Add the results from steps 2 and 3
45+19=64
step 5
Subtract the number in step 4 from the next higher multiple of 10. In this example, the next multiple of 10 after 64 is 70, so subtract 64 from 70:
70-64=6
This number is not equal to the check digit (8)
therefore
Is not a valid code
The last digit should be 6 in order to make it a valid code
