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Kipish [7]
3 years ago
10

Humans are capable of vastly more complex thoughts and feelings due to the ever-adapting web of connection among?

Physics
1 answer:
salantis [7]3 years ago
3 0
Are there answer choices ?
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Small, slowly moving spherical particles experience a drag force given by Stokes' law: Fd = 6πηrv where r is the radius of the p
Dominik [7]

Answer:

Explanation:

At the time of a body achieving terminal velocity, the drag force becomes equal to the weight of the body less the buoyant force by the surrounding medium which can be represented by the following equation

\frac{4\pi\times r^3(d-\rho)}{3} =6\pi\times n\times r\times v

Where r is radius of the body , d is density of the material of the body σ is density of the medium and n is coefficient of viscosity of the medium and v is terminal velocity.

Simplifying

v = \frac{2\times r^2(d-\rho)}{9\times n}

Assuming the value of density of air as 1.225 kg/m³ and putting other given values in the formula we get

v = [tex]\frac{2\times (1.2\times10^{-5})^2(2182-1.225)}{9\times 1.8\times10^{-5}}[/tex]

v = 387 x 10⁻⁵ m/s

Terminal velocity = 387 x 10⁻⁵ m/s

Time taken to fall a distance of 100 m

= \frac{100}{387\times10^{-5}}

= 2.6 x 10⁴ s.

5 0
3 years ago
Your GPS shows that your friend’s house is 10.0 km away. But there is a big hill between your houses and you don’t want to bike
kati45 [8]

Answer:

The value is c  = 8 \  km

Explanation:

From the question we are told that

The distance of friends house from your point is a =  10 \  km

The distance of your friends street from your street is b =  6 \  km \  in the \ direction \  towards \  the  \  north

The diagram illustrating this question is shown on the first uploaded image

From the diagram we can apply by Pythagoras theorem as follows

a^2 =  b^2 +  c^2

=>     c  =  \sqrt{^2 -  b^2}

=>     c  =  \sqrt{ 10^2 -  6^2}

=>     c  = 8 \  km

6 0
4 years ago
Oil _____.
atroni [7]
Oil <span>must be mined from underground 

Oil is NOT a renewable resource
Oil does NOT release more toxins than coal
Oil also is NOT easily replenished

</span>
4 0
4 years ago
Read 2 more answers
Suppose you push a hockey puck of mass m across frictionless ice for a time \Delta t, starting from rest, giving thepuck speed v
bazaltina [42]

Answer:

1. t_2 = 2t_1

2. t_2 = t_1\sqrt{2}

Explanation:

1. According to Newton's law of motion, the puck motion is affected by the acceleration, which is generated by the push force F.

In Newton's 2nd law: F = ma

where m is the mass of the object and a is the resulted acceleration. So in the 2nd experiment, if we double the mass, a would be reduced by half.

a_1 = 2a_2

Since the puck start from rest, in the 1st experiment, to achieve speed of v it would take t time

t = v / a_1

Now that acceleration is halved:

t = \frac{v}{2a_2}

\frac{v}{a_2} = 2t

You would need to push for twice amount of time t_2 = 2t_1

2. The distance traveled by the puck is as the following equation:

d = at^2

So if the acceleration is halved while maintaining the same d:

\frac{d_1}{d_2} = \frac{a_1t_1^2/2}{a_2t_2^2/2}

As d_1 = d_2, then d_1/d_2 = 1. Also a_1 = 2a_2

1 = \frac{2a_2t_1^2}{a_2t_2^2}

t_2^2 = 2t_1^2

t_2 = t_1\sqrt{2}\approx 1.14t_1

So t increased by 1.14

7 0
3 years ago
Determine the potential difference between two charged parallel plates that are 0.20 cm apart and have an electric field strengt
Nesterboy [21]
V=Ed=0.20\times 6=1.20
8 0
3 years ago
Read 2 more answers
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