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Maksim231197 [3]
2 years ago
8

An airplane accelerates down a runmway at 2.9 m/s/s for 38.5 seconds

Physics
2 answers:
Serhud [2]2 years ago
8 0

Given,

the initial velocity = 0 m /s.

acceleration = 3.20 m / s^2

time = 32.8 s

According to laws of motion.

s = ut + 1/2 at ^2

s = 1/2 at²

s=1/2(3.20)(32.8)²

s= 1721.344 m

the distance traveled before takeoff is 1731.3m

inessss [21]2 years ago
3 0
  • initial velocity=u=0m/s^2
  • Acceleration=2.9m/s^2
  • Time=t=38.5s

Distance be s

\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2

\\ \sf\longmapsto s=0(38.5)+\dfrac{1}{2}(2.9)(38.5)^2

\\ \sf\longmapsto s=1.45(1482.25)

\\ \sf\longmapsto s=2149.26m

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