Answer:
B) 0.6M
Explanation:
I apologize in advance if it is not correct :l
The (M1V1= M2V2) is given for you to plug in the correct numbers so let's jot this down.
(M1*V1= M2*V2)
so they give us 6M which would be our (M1), from this we can also conclude that 5mL is also V1; ( if you notice the M1's and V1's are always found next to eachother). This leads us to our 50mL, this would be our V2 because the volume went from 5mL to 50mL. Now lets put this in order based on what we know.
M1= 6M (M1*V1= M2*V2)
V1= 5mL
M2= ?
V2= 50mL
now we plug in what we know into the equation to find the unknown (M2)
(6M*5mL= M2*50mL)
now we could do the long math, but I don't think your on brainly to do the hard way. so lets keep it simple!
We are going to put the 50mL under the (6M*5mL) for division.
This is honestly MUCH easier, than manually answering. you just put that in the calculator and it'll give you B) 0.6M
honestly though I might not know what I'm doing cuz im currently doing my test and decided to answer this question ;)
Good Luck!
Answer:
1.2×10²³ atoms.
Explanation:
Data obtained from the question include:
Mole of propanone = 0.20 mole
Number of atoms of propanone =.?
From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.022×10²³ atoms.
This implies that 1 mole of propanone also contains 6.022×10²³ atoms.
Thus, we can obtain the number of atoms in 0.20 mole of propanone as illustrated below:
1 mole of propanone contains 6.022×10²³ atoms.
Therefore, 0.20 mole of propanone will contain = 0.2 × 6.022×10²³ = 1.2×10²³ atoms.
Thus, 0.20 mole of propanone contain
1.2×10²³ atoms.
Answer:
yes. they can block the wind which causes top soil erosion and they also soak up some the water in the soil
I would be difficult to remove an electron from a Noble or Inert Gas (also known as the group 8 or 0 elements). This is because they all have filled outermost shells and as such the outermost shell would be held tightly to the nucleus and as such make it difficult to remove. Examples Helium, Neon, Argon, Xenon, Krypton and Radon
Molar mass of empirical formula = 172.8 g/mole
346.6g/172.8 g/mole = 2.00 moles
Molecular formula = C2H2Br4
