Question

Se deja resbalar por un plano inclinado de 30° un cuerpo de 15kg. Calcular la aceleración con la que desciende suponiendo que no hay rozamiento

Answer 1

Answer:

$4.9 m/s^2$

Explanation:

In order to find the acceleration of the block, we have to find the net force acting on it along the direction parallel to the incline.

However, there is only one force acting on the block along this direction: it is the component of the weight parallel to the plane, given by

$mg sin \theta$

where

m = 15 kg is the mass of the block

$g=9.8 m/s^2$ is the acceleration of gravity

$\theta=30^{\circ}$ is the angle of the incline

According to Newton's second law, the net force is proportional to the acceleration, a:

$F=ma$

So we can write:

$ma = mg sin \theta$

And so, the acceleration is:

$a=g sin \theta = (9.8)(sin 30^{\circ})=4.9 m/s^2$