3 years ago

Iff(x)=x^2+2x-4and g(x)=3x+1 find f(g(x))=x^2+x+__

Mathematics

1 answer:

Korvikt [17]3 years ago

7 0

Step-by-step explanation:

f(x) = x² + 2x - 4

g(x) = 3x + 1

f(g(x)) = f(3x + 1)

f(3x + 1) = [3x + 1]² + 2[3x + 1] - 4

= 9x² + 6x + 1 + 6x + 2 - 4

= 9x² + 12x -1

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Iff(x)=x^2+2x-4and g(x)=3x+1 find f(g(x))=__x^2+__x+__​

Iff(x)=x^2+2x-4and g(x)=3x+1 find f(g(x))=x^2+x+__