When writing equivalent expressions, there are often several possible orders in which to simplify them. However, they will all take you to the same result as long as you do not make a mistake when using the properties. In this example, you will distribute the outer exponent first using the Power of a Product Property.
Wat r u asking about this problem
Answer:
Its either L or N im not sure but if i had to guess out of the two i think its L.
Step-by-step explanation:
Answer:
Test statistic = - 0.851063
- 2.520463
Step-by-step explanation:
H0 : μ ≥ 15
H1 : μ < 15
Sample mean, xbar = 14.5
Sample standard deviation, s = 4.7
Sample size = 64
Teat statistic :
(xbar - μ) ÷ (s/√(n))
(14.5 - 15) ÷ (4.7/√(64))
= - 0.851063
The critical value at α = 0.05
Using the T - distribution :
Degree of freedom, df = 64 - 1 = 63
Tcritical(0.05, 63) = 1.6694
Test statistic - critical value
-0.851063 - 1.6694
= - 2.520463