Answer:
a) 0.15
b) 0.2
c) 0.6
Step-by-step explanation:
We are given the following in the question:
A: Stopping at first signal
B: Stopping at second signal
P(A) = 0.35
P(B) = 0.55
Probability that he must stop at at least one of the two signals is 0.75
![P(A\cup B) = 0.75](https://tex.z-dn.net/?f=P%28A%5Ccup%20B%29%20%3D%200.75)
a) P(at both signals)
![P(A\cup B) = P(A) + P(B) - P(A\cap B)\\0.75 = 0.35 + 0.55 - P(A\cap B)\\P(A\cap B) = 0.35 + 0.55 - 0.75 = 0.15](https://tex.z-dn.net/?f=P%28A%5Ccup%20B%29%20%3D%20P%28A%29%20%2B%20P%28B%29%20-%20P%28A%5Ccap%20B%29%5C%5C0.75%20%3D%200.35%20%2B%200.55%20-%20P%28A%5Ccap%20B%29%5C%5CP%28A%5Ccap%20B%29%20%3D%20%200.35%20%2B%200.55%20-%200.75%20%3D%200.15)
0.15 is the probability that motorist stops at both signals.
b) P(at the first signal but not at the second one)
![P(A\cap B') = P(A) - P(A\cap B)\\P(A\cap B') = 0.35 - 0.15 = 0.2](https://tex.z-dn.net/?f=P%28A%5Ccap%20B%27%29%20%3D%20P%28A%29%20-%20P%28A%5Ccap%20B%29%5C%5CP%28A%5Ccap%20B%27%29%20%3D%200.35%20-%200.15%20%3D%200.2)
0.2 is the probability that motorist stops at the first signal but not at the second one.
c) P(at exactly one signal)
![P(A\cap B') + P(A\cap 'B) = P(A\cup B) - P(A\cap B) \\P(A\cap B') + P(A\cap 'B) = 0.75 - 0.15 = 0.6](https://tex.z-dn.net/?f=P%28A%5Ccap%20B%27%29%20%2B%20P%28A%5Ccap%20%27B%29%20%3D%20P%28A%5Ccup%20B%29%20-%20P%28A%5Ccap%20B%29%20%5C%5CP%28A%5Ccap%20B%27%29%20%2B%20P%28A%5Ccap%20%27B%29%20%3D%200.75%20-%200.15%20%3D%200.6)
0.6 is the probability that the motorist stops at exactly one signal.
Too easy
remember all angles in traingle add to 180
straight lnes are 180
so
35+59+x=triangle
35+59+x=180
x=86
x+y=line
x+z=180
86+z=180
z=94
11+z+y=triangle
11+94+y=180
y=75
x=86
y=75
z=94
yah, 2nd one
Step-by-step explanation:
x + 2x + 3x = 180°
6x = 180°
Therefore, x = 30°
2 x = 60°
3x = 90°
Hence, it is a right angled triangle.
2+4(78)/23-6^8:9/2 your welcome