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andreyandreev [35.5K]
3 years ago
13

Can someone please help me with 10-16 it’s due tomorrow!!! Please

Mathematics
1 answer:
VMariaS [17]3 years ago
7 0
10) V=πr² *h= π*10²*12≈3770
11) V=A(base)*h= (3√3/2)*(9²)*10=2104
A(base)=(P*a)/2=(6*9*3√3)/2=9*9*3√3/2

12)V=πr² *h=π*18² *6≈6107
13)V=4*3*12=144
14) h(triangle)=√(5²-3²)=√16=4
A(base)=(3*4)/2=6
V=A(base)* height (prism)=6*2=12
15)  V=A(base)*h= (3√3/2)*(6²)*11= 1029
16)V=A(base)*h=2(1+√2)5²*22≈2656
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Sanchez-97

Washington-117

Step-by-step explanation:

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Henry is staining the wooden floor of a court. The court is in the shape of a rectangle. Its length is 54 feet and its width is
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Henry would need 12 cans to cover the court

Step-by-step explanation:

1: 30 times 54 = 1620

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8 0
3 years ago
What is the equation of a circle with center (-3, -1) that contains the point (1, 2)?
Leno4ka [110]
So, we know the center is at -3,-1, ok

hmmm what's the radius anyway?   well, we know that there's a point at 1,2 that is on the circle's path...hmmmm what's the distance from the center to that point?  well, is the radius, let's check then.

\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ -3}}\quad ,&{{ -1}})\quad 
%  (c,d)
&({{ 1}}\quad ,&{{ 2}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
r=\sqrt{[1-(-3)]^2+[2-(-1)]^2}\implies r=\sqrt{(1+3)^2+(2+1)^2}
\\\\\\
r=\sqrt{16+9}\implies r=\sqrt{25}\implies r=5

so, what's the equation of a circle with center at -3, -1 and a radius of 5?

\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{\quad  k}})\qquad 
radius=&{{ r}}\\
&-3&-1&5
\end{array} 
\\\\\\\
[x-(-3)]^2+[y-(-1)]^2=5^2\implies (x+3)^2+(y+1)^2=25
7 0
3 years ago
Write the equation for the inverse of the function y=Cos^-1(x-pi)
ser-zykov [4K]

we are given

y=cos^{-1}(x-\pi)

Since, we have to find inverse function

step-1:

Set y=f(x)

It is already there

step-2:

Switch x and y

x=cos^{-1}(y-\pi)

step-3: Solve for y

We can take cos on both sides

cos(x)=cos(cos^{-1}(y-\pi))

we can simplify it

cos(x)=y-\pi

now, we can solve for y

cos(x)+\pi=y-\pi+\pi

cos(x)+\pi=y

y=\pi +cos(x)..............Answer


3 0
3 years ago
Read 2 more answers
A car initially traveling at 20 kilometers per hour takes 10 seconds to speed up to 70 km/hour. At what rate is it changing spee
Snezhnost [94]
  • Initial velocity=u=20km/h
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Convert speeds to m/s

\\ \rm\longmapsto u=20\times\dfrac{5}{18}=5.05m/s

\\ \rm\longmapsto v=70\times \dfrac{5}{18}=19.4m/s

\boxed{\sf Acceleration=\dfrac{v-u}{t}}

\\ \rm\longmapsto Acceleration=\dfrac{19.4-5.05}{10}

\\ \rm\longmapsto Acceleration=\dfrac{14.3}{10}

\\ \rm\longmapsto Acceleration=143m/s^2

7 0
2 years ago
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