3 years ago

Can someone please help me with 10-16 it’s due tomorrow!!! Please

1 answer:

7 0

10) V=πr² *h= π*10²*12≈3770
11) V=A(base)*h= (3√3/2)*(9²)*10=2104
A(base)=(P*a)/2=(6*9*3√3)/2=9*9*3√3/2

12)V=πr² *h=π*18² *6≈6107
13)V=4*3*12=144
14) h(triangle)=√(5²-3²)=√16=4
A(base)=(3*4)/2=6
V=A(base)* height (prism)=6*2=12
15) V=A(base)*h= (3√3/2)*(6²)*11= 1029
16)V=A(base)*h=2(1+√2)5²*22≈2656

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in isosceles triangle the length of a leg is 17 cm, the vase is 16 cm. find the length of the altitude to the base

bogdanovich [222]

Answer:

15 cm

Step-by-step explanation:

The altitude is one leg of the right triangle formed by the altitude, half the base, and the triangle side. The Pythagorean theorem applies, so you have ...

... (17 cm)² = (altitude)² + (16 cm/2)²

... altitude = √(17² -8²) cm = √225 cm

... altitude = 15 cm