Without graphing the linear functions, find the coordinates of the point of intersection of their graphs: y=3x−11 and y=4
1 answer:
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First, we will use the distributive property (order of operations) to simplify the equation:
(4)(5) + (4)(−8(4c−3)) = (12)(1) + (12)(−13c)+ (−8) =
20 + (−128c) + 96 = 12 + (−156c)+ (−8)
Now, we will combine like terms to simplify the equation:
(−128c) + (20 + 96) = (−156c) + (12+ (−8) =
−128c + 116 = −156c + 4
Now we will add 156 to both sides, using inverse operations.
−128c + 116 + 156c = −156c + 4 + 156c =
28c + 116 = 4
Now we will subtract 116 from both sides:
28c + 116 − 116 = 4 − 116 =
28c = −112
Lastly, we will divide both sides by 28:
28c/28 = c
-112/28 = -4
The equation now looks like:
c = -4
Therefore, your answer is -4.
Answer:
Therefore, the standard for will be:
Step-by-step explanation:
The equation of a parabola written as vertical axes is given by:
(1)
The vertex of the parabola (h,k) is (2,-5).
The focus (h,k+p) is (2,-4)
Then we can find p knowing that:
h = 2
k = -5
k + p = -4 then p = -4+5 = 1
Putting all these values in equation (1) we will find the equation of the parabola:
(2)
Now, we need to find the standard form of the equation of the parabola.
Let's recall that standard form is:
We just need to work out equation (2) to convert it to the standard form.
Therefore, the standard for will be:
I hope it helps you!