Which way is counterclockwise?

Mathematics

1 answer:

tensa zangetsu [6.8K]3 years ago

7 0

Answer:

B. the opposite way the hands move on a clock

You might be interested in

Find the value of the integral that converges.<br> ∫^-5_-[infinity] x^-2 dx.

Bingel [31]

Answer:

$\int_{-\infty}^{-5} x^{-2}dx= \frac{1}{5} + \lim_{x\to -\infty} \frac{1}{x} =\frac{1}{5}$

Because the $\lim_{x\to -\infty} \frac{1}{x} =0$

The integral converges to $\frac{1}{5}$

Step-by-step explanation:

For this case we want to find the following integral:

$\int_{-\infty}^{-5} x^{-2}dx$

And we can solve the integral on this way:

$\int_{-\infty}^{-5} x^{-2}dx= \frac{x^{-2+1}}{-2+1} \Big|_{-\infty}^{-5}$

$\int_{-\infty}^{-5} x^{-2}dx= -\frac{1}{x} \Big|_{-\infty}^{-5}$

And if we evaluate the integral using the fundamental theorem of calculus we got:

$\int_{-\infty}^{-5} x^{-2}dx= \frac{1}{5} + \lim_{x\to -\infty} \frac{1}{x} =\frac{1}{5}$

Because the $\lim_{x\to -\infty} \frac{1}{x} =0$

The integral converges to $\frac{1}{5}$

8 0

3 years ago

These are the weekly wages paid to staff in a hotel.

Marianna [84]

If I’m not mistaken 174 is your median

5 0

3 years ago

This is my last question can someone help me with my homework.

shutvik [7]

9514 1404 393

Answer:

C, A, A

Step-by-step explanation:

In general, you ...

identify the coefficients of one of the variables
swap them, and negate one of them
multiply the corresponding equations by the "adjusted" coefficients.

In problem 1, the x-coefficients are 8 and 2. A common factor of 2 can be removed so that we're dealing with the numbers 4 and 1. Assuming we want to multiply one of the equations by 1, leaving it unchanged, the value we want to multiply by will be -4. After we swap the coefficients, that multiplier is associated with equation 2:

multiply equation 2 by -4 . . . (eliminates x)

Likewise, the y-coefficients in problem 1 are -1 and 3. Again, if we want to multiply one of the equations by 1, leaving it unchanged, the coefficient we will change the sign of is -1 (becomes 1). After we swap the coefficients, the multiplier 3 is associated with equation 1:

multiply equation 1 by 3 . . . (eliminates y)

These two choices are B and A, respectively, so the one that does NOT work for problem 1 is choice C, as indicated below.

The other problems are worked in a similar fashion.