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xeze [42]
3 years ago
15

This is my last question can someone help me with my homework.

Mathematics
1 answer:
shutvik [7]3 years ago
8 0

9514 1404 393

Answer:

  C, A, A

Step-by-step explanation:

In general, you ...

  • identify the coefficients of one of the variables
  • swap them, and negate one of them
  • multiply the corresponding equations by the "adjusted" coefficients.

__

In problem 1, the x-coefficients are 8 and 2. A common factor of 2 can be removed so that we're dealing with the numbers 4 and 1. Assuming we want to multiply one of the equations by 1, leaving it unchanged, the value we want to multiply by will be -4. After we swap the coefficients, that multiplier is associated with equation 2:

  multiply equation 2 by -4 . . . (eliminates x)

Likewise, the y-coefficients in problem 1 are -1 and 3. Again, if we want to multiply one of the equations by 1, leaving it unchanged, the coefficient we will change the sign of is -1 (becomes 1). After we swap the coefficients, the multiplier 3 is associated with equation 1:

  multiply equation 1 by 3 . . . (eliminates y)

These two choices are B and A, respectively, so the one that does NOT work for problem 1 is choice C, as indicated below.

__

The other problems are worked in a similar fashion.

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HELP! &lt;3<br><br> I have other questions as well not yet posted, if you'd like more points! :3
ratelena [41]

Option B: \frac{AB}{BC}=\frac{AE}{ED} is sufficient to prove that BE ll CD

Explanation:

Given that ACD is a triangle.

The line EB intersects the sides AC and AD of the triangle.

The point E intersect the side AD and B intersect the side AC.

We need to prove that BE ll CD

Then, the side splitter theorem states that "If a line intersects two sides of a triangle and divides the sides proportionally, the line is parallel to the third side of the triangle".

From the side splitter theorem, the line EB intersects the two sides of the triangle AC and AD and divides the sides proportionally.

Thus, the proportion of the sides is given by

\frac{AB}{BC}=\frac{AE}{ED}

This proportionality shows that the line is parallel to the third side of the triangle.

Hence, \frac{AB}{BC}=\frac{AE}{ED} is sufficient to prove that BE ll CD

Therefore, Option B is the correct answer.

3 0
2 years ago
Factor out the GCF: 16x + 48​
valentinak56 [21]

Answer: 16(x + 3)

Step-by-step explanation: When you're asked to a polynomial, the first thing you want to look for is the greatest common factor between the terms that are involved.

So what is the greatest common factor of 16x and 48?

The greatest common factor of 16x and 48 is 16 because

it's the largest number that divides evenly into 16 and 48.

The x does not qualify because it must appear in every term

to qualify for the GCF but here, it only appears in one term.

So a 16 factors out leaving us with each term divided by it

inside a set of parentheses so w eget 16(x + 3).

Notice that if we distributed the 16 through both terms,

we would end up with our original polynomial.

7 0
3 years ago
Does this table represent a function ? Why or why not ​
LuckyWell [14K]
B- i could be wrong though
3 0
2 years ago
From a height of 50 meters above sea level on a cliff, two ships are sighted due west. The angles of depression are 61° and 28°.
Olenka [21]

Answer:

The ships are 66 meters apart.

Step-by-step explanation:

For the sake of convenience, let us label ships A and B

As shown in the figure, the distances to the ships from right triangles.

The distance to the ship A is d_1 and it is given by

tan (61^o)= \dfrac{50}{d_1}

d_1=\dfrac{50}{tan (61^o)}

\boxed{d_1= 27.71m}

And the distance to the ship B is d_2 and is given by

tan (28^o)= \dfrac{50}{d_2}

d_2=\dfrac{50}{tan (28^o)}

\boxed{ d_2=94.04m}

Therefore, the distance d between the ships A and B is

d= d_2-d_1=94.04-27.7\\\\\boxed{d=66m}

In other words, the ships are 66 meters apart.

8 0
3 years ago
Read 2 more answers
Please help with 18 and 19 ASAP ill do brainiac
DanielleElmas [232]

Answer:

18). y = -x

19). y = -2x + 4

3 0
3 years ago
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