Question

4 question in one 65 points

Answer 1

Q6.

The slope-intercept form: y = mx + b

m - slope

b - y-intercept

We have: slope m = 3, y-intercept (0, 4) → b= 4

Answer: y = 3x + 4

Q7.

2x + 4y = 4     |subtract 2x from both sides

4y = -2x + 4     |divide both sides by 4

y = -0.5x + 1

Only second graph has y-intercept = 1.

Answer: The second graph.

Q8.

The point-slope form:

$y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

We have

$(-16,\ 8)\to x_1=-16,\ y_1=8\\(4,\ -2)\to x_2=4,\ y_2=-2$

Substitute:

$m=\dfrac{-2-8}{4-(-16)}=\dfrac{-10}{20}=-\dfrac{1}{2}\\\\y-8=-\dfrac{1}{2}(x-(-16))\\\\y-8=-\dfrac{1}{2}(x+16)$

Answer: The first equation.

Q9.

It's a vertical line. The equation of a vertical line is x = a, where a is any real number.

Answer: x = -4

Answer 2

Answer:

Answer = y = 3x + 4

Answer = The second graph

Answer = The first equation.

Answer = -4

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(i drew each answers explanation but it wont let me upload the pic)