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k0ka [10]
3 years ago
5

A toy airplane, flying in a horizontal, circular

Physics
2 answers:
Dmitriy789 [7]3 years ago
6 0

The average speed of the airplane is 8.4 m/s

<h3>Further Explanation</h3>

<u>Given :</u>

number of rotation = N = 10

time intervals = Δt  = 30 s

radius = R = 4.0 m

<u>Unknown :</u>

average speed = v = ?

<u>Solution :</u>

v = ω × R

v = ( θ / Δt ) × R

v = ( 10 × 2π / 30 ) × 4

v = (8π / 3) m/s

<h2>v ≈ 8.4 m/s</h2>

<h3>Learn more</h3>

Newton's Law of Motion: brainly.com/question/10431582

Example of Newton's Law: brainly.com/question/498822

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Dynamics

Keywords: Newton, Law, Impulse, Work

Goshia [24]3 years ago
4 0

Answer:

8.4 m/s

Explanation:

The toy completes 10 circle in 30 seconds. So its frequency of revolution is

f=\frac{10}{30 s}=0.33 Hz

The periof of revolution is the reciprocal of the frequency, so

T=\frac{1}{f}=\frac{1}{0.33 Hz}=3 s

The radius of the circular path is

r = 4.0 m

So the total distance covered by the toy in one circle is the length of the circumference:

2\pi r

And so the average speed is

v=\frac{2\pi r}{T}=\frac{2\pi (4.0 m)}{3 s}=8.4 m/s

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Balanced equation is:
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5 0
2 years ago
Calculate the density of a substance that has mass 10g and volume 2mL
noname [10]

You're supposed to divide the mass by the volume, which is going to equal to 5

4 0
3 years ago
The rock and meterstick balance at the 25-cm mark, as shown in the sketch. The meterstick has a mass of 1 kg. What must be the m
liraira [26]

Answer:

<h2>1 kg</h2>

Explanation:

Check the diagram attached below for the diagram.

Let the weight of the rock be W and the mass of the meter stick be M. Note that the mass of the meter stick will be placed at the middle of the meter stick i.e at the 50cm mark

Using the principle of moment to calculate the weight of the rock. It states that the sum of clockwise moments is equal to the sum of anti clockwise moment.

Moment = Force * perpendicular distance

The meterstick acts in the clockwise direction while the rock acys in the anti clockwise direction

Clockwise moment = 1kg * 25 = 25kg/cm

Anticlockwise moment = W * 25cm = 25W kg/cm

Equating both moments of forces

25W = 25

W = 25/23

W = 1 kg

The mass of the rock is also 1 kg

3 0
3 years ago
before colliding, the momentum of block A is +15.0 kg m/s. after, block A has a momentum -12.0 kg*m/s. what is the momentum of b
Helen [10]

Answer:

The momentum of block B = 27 Kg m/s

Explanation:

Given,

The initial momentum of block A, MU = 15 Kg m/s

The final momentum of block A, MV = -12 Kg m/s

Consider the block B is initially at rest.

Therefore, the initial momentum of block B, mu = 0

According to the laws of conservation of linear momentum, the momentum of the body before impact is equal to the momentum of the body after impact.

                               <em> MU + mu = MV + mv</em>

                                15  +  (0) = (-12) + mv

                                         mv = 15 + 12

                                              =  27 Kg m/s

Hence, the momentum of the block B after impact is, mv = 27 Kg m/s

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2 years ago
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Certain electrons in the dye molecule move to a higher energy level, with the difference in energy between the lower and higher energy levels being the same as the energy of the absorbed photons.
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