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3 years ago

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Optical tweezers use light from a laser to move single atoms and molecules around. Suppose the intensity of light from the tweez

ers is 1000 W/m2, the same as the intensity of sunlight at the surface of the Earth. (a) What is the pressure on an atom if light from the tweezers is totally absorbed

1 answer:

katrin [286]3 years ago

4 0

Answer:

a= 4.4×10 m/s^2

Explanation:

pressure P = E/c

Where, E = 100 W/m^2 intensity of light

c= speed of light = 3×10^8 m/s

P = 1000/ 3×10^8

P = 3.33×10^(-6) Pa

Force F = P×A

P is the pressure and c= speed of light

F = 3.33×10^{-6}×6.65×10(-29)

= 2.22×10^{-6}

acceleration a = F/m = 2.22×10^{-6}/ 5.10×10^{-27}

a= 4.4×10 m/s^2

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High rate of evaporation in a water cycle can most likely cause

scoray [572]

Answer: d. thunderstorms
The option <span>blizzards can be excluded as it is clearly not related to the evaporation. Floods can happen if the condensation rate high, not evaporation. Sometimes the cloud that carries water is just blown up by the wind so the evaporation does not happen in that place.
Thunderstorms happen more in summer because the rate of evaporation and condensation is increased.</span>

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4 years ago

Read 2 more answers

If a 2kg ball has and initial velocity of

lakkis [162]

Answer:

$\boxed {\boxed {\sf 12 \ Newtons }}$

Explanation:

Force is equal to the product of mass and acceleration.

$F=m*a$

We know the mass, but not the acceleration. Therefore, we must calculate it before we can calculate force.

1. Calculate Acceleration

Acceleration is the change in velocity over the change in time.

$a=\frac{V_f-V_i}{t}$

The final velocity is 10 meters per second and the initial velocity is 4 meters per second. The time is 1 second.

$V_f=10 \ m/s \\V_i= 4 \ m/s \\t= 1 \ s$

Substitute the values into the formula.

$a=\frac{10 \ m/s-4 \ m/s }{1 \ s}$

Solve the numerator.

$a=\frac{6 \ m/s}{1 \ s }$

Divide.

$a= 6 \ m/s/s=6 \ m/s^2$

2. Calculate Force

Now we know the acceleration and the mass.

$m= 2 \ kg \\a= 6 \ m/s^2$

Substitute the values into the fore formula.

$F= 2 \ kg * 6 \ m/s^2$

Multiply.

$F= 12 \ kg*m/s^2$

1 kilogram meter per square second is equal to 1 Newton.
Our answer of 12 kg*m/s² is equal to 12 Newtons

$F= 12 \ N$

The force applies to the ball was <u>12 Newtons.</u>

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3 years ago

A 98.0 N grocery cart is pushed 12.0 m along an aisle by a shopper who exerts a constant horizontal force of 40.0 N. If all fric

Digiron [165]

Answer:

9.8 m/s

Explanation:

The work done by the force pushing the cart is equal to the kinetic energy gained by the cart:

$W=K_f -K_i$

where

W is the work done

$K_f$ is the final kinetic energy of the cart

$K_i$ is the initial kinetic energy of the cart, which is zero because the cart starts from rest, so we can write:

$W=K_f$

But the work is equal to the product between the pushing force F and the displacement, so

$W=Fd=(40.0 N)(12.0 m)=480 J$

So, the final kinetic energy of the cart is 480 J. The formula for the kinetic energy is

$K_f=\frac{1}{2}mv^2$ (1)

where m is the mass of the cart and v its final speed.

We can find the mass because we know the weight of the cart, 98.0 N:

$m=\frac{F_g}{g}=\frac{98.0 N}{9.8 m/s^2}=10 kg$

Therefore, we can now re-arrange eq.(1) to find the final speed of the cart:

$v=\sqrt{\frac{2K_f}{m}}=\sqrt{\frac{2(480 J)}{10 kg}}=9.8 m/s$

7 0

3 years ago

A 5kg baby is asleep in a 5kg stroller. The mom is speed walking in the park at 3m/s. How much momentum does she generate with t

lesya [120]

Answer:

The correct solution is "15 kgm/s". A further explanation is given below.

Explanation:

The given values are:

Mass,

m = 5 kg

Velocity,

v = 3 m/s

By applying the formula of momentum, we get

⇒ $P=m v$

On substituting the given values, we get

⇒ $=5\times 3$

⇒ $=15 \ kgm/s$

6 0

3 years ago

Find the magnitude of the resultant force and the angle it makes with the positive x-axis. (Let a = 200 N and b = 400 N. Round y

omeli [17]

Answer: R = 346.4N and angle 30° to the horizontal negative axis

Explanation:

To find the resultant force, we need to sum up the forces on the vertical and horizontal axis.

For the horizontal axis;

Rx = -b + acos60

Rx = -400N +200cos60

Rx = -400N +100N

Rx = -300N

For the vertical axis;

Ry = asin60 = 200sin60

Ry = 173.2N

The resultant force R can be given as;

R = √(Rx^2 +Ry^2)

R = √((-300)^2 + 173.2^2)

R = 346.4N

Angle z can be written as

Tanz = Ry/Rx

z = taninverse (Ry/Rx)

z = taninverse (173.2/300)

z = 30°

6 0

3 years ago