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Troyanec [42]
3 years ago
14

Match the term to the correct description.

Physics
2 answers:
Sedaia [141]3 years ago
7 0
1. Proton
2. negative ion
3. electric charge
4. electron
5. repel
6. attract
7. positive ion
Lena [83]3 years ago
6 0
1.Positive
2.Positive Ion
3.Electric charge
4.Electron
5.Repel
6.Attract
7.Negative Ion 

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A cart with a mass of 0.5 kg is at the top of the ramp. The height is 0.40m .
Tju [1.3M]

A=0.05.0M.

B=68.9244GPE.34

C=0

D it would be 79%HIGHER

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3 years ago
The chocolate in your favorite candy bar has the chemical formula: C7H8N4O2. What elements are present in this formula? Carbon,
fenix001 [56]

Carbon, hydrogen, nitrogen and oxygen are all non metals.

5 0
3 years ago
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Fossil fuels store energy from the sun as<br><br> question 5
qwelly [4]

Answer:

Fossil fuels store energy from the sun as

Explanation:

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3 years ago
Particle moves in a circle of radius 90m with a constant speed 25m/s. how many revolution does it make in 30sec​
Serggg [28]

Answer:

<em>n =1.33 revolutions</em>

Explanation:

<u>Uniform Circular Motion</u>

The angular speed can be calculated in two different ways:

\displaystyle \omega=\frac{v}{r}

Where:

v = tangential speed

r = radius of the circle described by the rotating object

Also:

\omega=2\pi f

Where:

f = frequency

Solving for f:

\displaystyle f=\frac{\omega}{2\pi}

Since the frequency is calculated when the number of revolutions n and the time t are known:

\displaystyle f=\frac{n}{t}

We can solve for n:

n=f.t

The particle moves in a circle of r=90 m with a speed v=25 m/s. Thus the angular speed is:

\displaystyle \omega=\frac{25}{90}

\displaystyle \omega=0.278\ rad/s

Now we calculate f:

\displaystyle f=\frac{0.278}{2\pi}

f=0.04421\ Hz

Calculating the number of revolutions:

n = 0.04421*30

n =1.33 revolutions

8 0
3 years ago
In a photoelectric effect experiment, electrons emerge from a copper surface with a maximum kinetic energy of 1.10 eV when light
Sladkaya [172]

Answer:A) 220 nm

Explanation:

Given

Maximum Kinetic Energy K.E.=1.10 eV

Work Function W=4.65 eV

from Einstein Equation

h\mu =W+K.E.

h\cdot \frac{c}{\lambda }=W+K.E.

h\cdot \frac{c}{\lambda }=4.65+1.10

6.626\times 10^{-34}\cdot \frac{3\times 10^8}{\lambda }=5.75

1 eV=1.6\times 10^{-19} J

thus 5.75 eV=9.2\times 10^{-19} J

\lambda =\frac{6.626\times 10^{-34}\time 3\times 10^8}{9.2\times 10^{-19}}

\lambda =216.06 nm\approx 220 nm

6 0
3 years ago
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