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Harman [31]
3 years ago
12

Which of the following is not the same as 8,540 centigrams?

Chemistry
2 answers:
Dahasolnce [82]3 years ago
8 0
8.54 Probably a little too late but, hey better late than never lol
Mila [183]3 years ago
4 0

Missing question:

0.0854 kilogram  

85.4 grams  

8.54 hectograms  

85,400 milligrams.

Answer is: 8.54 hectograms is not the same.

1 cg = 0.01 g; one centigram is equal to 10⁻² grams.

m = 8540 cg.

m = 8540 cg · 0.01 g/cg.

m = 85.4 g.

1) m = 0.0854 kg.

1 kg = 1000 g.

m = 0.0854 kg · 1000 g/kg.

m = 85.4 g; it is the same.

2) m = 85.4 g; it is the same.

3) m = 8.54 hg.

1 hg = 100 g; one hectogram is 100 grams.

m = 8.54 hg · 100 g/hg.

m = 854 g; it is not the same.

4) m = 85400 mg.

1 mg = 0.001 g.

m = 85400 mg · 0.001 g/mg.

m = 85.4 g; it is the same.

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reduction at electrode B

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4 years ago
A solution has a pH = 4.63. What is the [H3O+] concentration?
LUCKY_DIMON [66]

Explanation:

The pH of a solution can you be found by using the formula

pH = - log [ { H_3O}^{+}]

Since we are finding the [H3O+] , substitute the value of the pH and find it's antilog

We have

4.63 =  -  log[ { H_3O}^{+}] \\ [ { H_3O}^{+}]   =  {10}^{ - 4.63}  \\   \\  = 2.344 \times  {10}^{ - 5} mol {dm}^{ - 3}

Hope this helps you

7 0
3 years ago
Why does the dilution equation, M 1 V 1 = M 2 V 2, work?
valentina_108 [34]

Answer:

d) The dilution equation works because the number of moles remains the same.

Explanation:

Let’s say that you have 1 mol of a solute in I L of solution. The concentration is 1 mol·L⁻¹. and <em>M</em>₁<em>V</em>₁ = 1 mol.

Now, you dilute the solution to a volume of 2 L. You still have 1 mol of solute, but in 2 L of solution. The new concentration is 0.5 mol·L⁻¹.

The volume has doubled, but the volume has halved, and <em>M</em>₂<em>V</em>₂ = 1 mol.

b) <em>Wrong</em>. The molar concentration changes on dilution.

c) <em>Wrong</em>. The volume changes on dilution.

a) <em>Wrong</em>, although technically correct, because if the moles don’t change, the mass doesn’t change either. However, the formula <em>M</em>₁<em>V</em>₁ has units mol·L⁻¹ × L = mol. Thus, in the formula, it is moles that are constant.

6 0
4 years ago
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5 0
3 years ago
Consider the reaction of 35.0 g of iron as follows:
77julia77 [94]

Explanation:

4Fe + 3O2 --> 2Fe2O3

Mass of  iron = 35g

<em>How many moles of iron react?</em>

The relationship between mass and moles is given as;

Moles = mass /  Molar mass

Molar mass of iron = 56g/mol

Number of moles = 35 / 56 = 0.625 mol

<em>How many moles of oxygen molecules must react?</em>

From the equation of the reaction;

4 mol of Fe reacts with 3 mol of Oxygen molecule

0.625 mol would react with x mol?

4 = 3

0.625 = x

x = 0.625 * 3 / 4 = 0.46875 mol

<em>How many moles of product form?</em>

From the equation of the reaction;

4 mol of Fe reacts to form 2 mol of Fe2O3

0.625 mol would form x mol of Fe2O3

4 = 2

0.625 = x

x = 0.625 * 2 / 4 = 0.3125 mol

<em>What mass of product forms?</em>

Moles = mass /  Molar mass

Mass = Molar mass * Moles = 159.69 g/mol * 0.3125 mol = 49.9g

8 0
4 years ago
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