When a certain isotope, such as Pa-231, is hit by a neutron, it will always split into the same smaller nuclei.

The product gas is then passed through a concentrated solution of KOH to remove the CO2. After passage through the KOH solution,

Kamila [148]

Answer: The mass percent of nitrogen gas in the compound is 13.3 %

Explanation:

Assuming the chemical equation of the compound forming product gases is:

$\text{Compound}\xrightarrow[CuO(s)]{Hot}N_2(g)+CO_2(g)+H_2O(g)$

Now, the product gases are treated with KOH to remove carbon dioxide.

We are given:

$p_{Total}=726torr\\P_{water}=23.8torr\\$

So, pressure of nitrogen gas will be = $p_{Total}-p_{water}=726-23.8=702.2torr$

To calculate the number of moles of nitrogen, we use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of nitrogen gas = 702.2 torr = 0.924 atm (Conversion factor: 1 atm = 760 torr)

V = Volume of nitrogen gas = 31.8 mL = 0.0318 L (Conversion factor: 1 L = 1000 mL)

T = Temperature of nitrogen gas = $25^oC=[25+273]K=298K$

R = Gas constant = $0.0821\text{ L. atm }mol^{-1}K^{-1}$

n = number of moles of nitrogen gas = ?

Putting values in above equation, we get:

$0.924atm\times 0.0318L=n\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 298K\\n_{mix}=\frac{0.924\times 0.0318}{0.0821\times 298}=0.0012mol$

To calculate the mass of nitrogen gas, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of nitrogen gas = 28 g/mol

Moles of nitrogen gas = 0.0012 moles

Putting values in above equation, we get:

$0.0012mol=\frac{\text{Mass of nitrogen gas}}{28g/mol}\\\\\text{Mass of nitrogen gas}=(0.0012mol\times 28g/mol)=0.0336g$

To calculate the mass percent of nitrogen gas in compound, we use the equation:

$\text{Mass percent of nitrogen gas}=\frac{\text{Mass of nitrogen gas}}{\text{Mass of compound}}\times 100$

Mass of compound = 0.253 g

Mass of nitrogen gas = 0.0336 g

Putting values in above equation, we get:

$\text{Mass percent of nitrogen gas}=\frac{0.0336g}{0.253g}\times 100=13.3\%$

Hence, the mass percent of nitrogen gas in the compound is 13.3 %

8 0

3 years ago

What is the density of water if you have 50.0 grams of water and a volume of 50.0 millimeters

Gnom [1K]

Answer:

$\boxed {\tt 1.0 \ g/mL}$

Explanation:

Density can be found by dividing the mass by the volume.

$d=\frac{m}{v}$

The mass of the water is 50.0 grams.

The volume of the water is 50.0 milliliters.

$m= 50.0\ g \\v=50.0 \ mL$

Substitute the values into the formula.

$d=\frac{50.0 \ g}{50.0 \ mL}$

Divide.

$d= 1.0 \ g/mL$

The density of the water is 1.0 grams per milliliter. Also, remember that the density of pure water is always 1.0 g/mL or g/cm³

8 0

3 years ago

Can you guys help me answer question 5 on homogeneous mixture tysm

hjlf

Answer:

Hope this helped :) good luck! ❤️

Explanation:

A coolant solution is a homogeneous mixture because the coolant particles are not chemically combined with the water (keep their properties) and they are evenly distributed throughout the water.

7 0

2 years ago

Q1.

dlinn [17]

Answer:

there are four peaks in the 13c NMR (B)

3 0

3 years ago

To balance the reaction what coefficients (numbers) are needed: HBr +KOH ---> KBr + H2O

Tom [10]

Answer:

H2Br + 2KOH ----- K2Br + 2H2O

5 0

3 years ago