All categories

3 years ago

What is the role of a strong acid catalyst in an elimination reaction?

Chemistry

1 answer:

Ivan3 years ago

8 0

Explanation:

An elimination reaction is a type of organic reaction in which two substituents are removed from a molecule in either a one or two-step mechanism. The one-step mechanism is known as the E2 reaction, and the two-step mechanism is known as the E1 reaction.

Another definiton is;

Elimination reaction, any of a class of organic chemical reactions in which a pair of atoms or groups of atoms are removed from a molecule, usually through the action of acids, bases, or metals and, in some cases, by heating to a high temperature. It is the principal process by which organic compounds containing only single carbon-carbon bonds (saturated compounds) are transformed to compounds containing double or triple carbon-carbon bonds (unsaturated compounds).

Strong Acids play two key roles in elimination reactions:

1. Without the acid catalyst, the reaction is painfully slow.

2. Acid greatly facilitates elimination of the leaving group.

You might be interested in

True or false organic protein catalysts are precipitates

Dmitry_Shevchenko [17]

The answer is true lol

7 0

3 years ago

A flashbulb of volume 1.70 mL contains O2(g) at a pressure of 2.30 atm and a temperature of 18.0°C. How many grams of O2(g)

Lady bird [3.3K]

Answer:

0.0001637 mol

Explanation:

PV = nRT

Very important formula in chem

2.3 atm * 0.0017 L = n * 0.082057 * 291 K

= 0.0001637 mol O2

This concept is very important in chem, practice it.

7 0

3 years ago

At STP, solid carbon can exist as graphite or as diamond. These two forms of carbon have(1) the same properties and the same cry

Umnica [9.8K]

Answer=4

Diamonds and graphite have different properties and different crystal structures.

In diamonds, the carbon atoms are arranged tetrahedrally, whereas carbon atoms are arranged in an infinite array in graphite. Graphite has a lower density than diamonds... Diamonds are the best conductor of heat that we know of... the properties differ greatly

3 0

3 years ago

A chemist must prepare 800.0mL of sodium hydroxide solution with a pH of 12.10 at 25°C. She will do this in three steps: Fill a

AnnZ [28]

Answer:

0.42 g

Explanation:

We have:

pH = 12.10 (25 °C)

V = 800.0 mL = 0.800 L

To find the mass of sodium hydroxide (NaOH) we can use the pH:

$14 = pH + pOH$

$pOH = 14 - pH = 14 - 12.10 = 1.90$

$pOH = -log ([OH^{-}])$

$[OH]^{-} = 10^{-pOH} = 10^{-1.90} = 0.013 M$

Now, we can find the number of moles (η) of OH:

$\eta = ([OH]^{-})*V = 0.013 mol/L * 0.800 L = 1.04 \cdot 10^{-2} moles$

Since we have 1 mol of OH in 1 mol of NaOH, the number of moles of NaOH is equal to 1.04x10⁻² moles.

Finally, with the number of moles we can find the mass of NaOH:

$m = \eta * M$

Where M is the molar mass of NaOH = 39.9 g/mol

$m = 1.04 \cdot 10^{-2} moles * 39.9 g/mol = 0.42 g$

Therefore, the mass of sodium hydroxide that the chemist must weigh out in the second step is 0.42 g.

I hope it helps you!

3 0

3 years ago

If 0.98 moles of BaCl2 are dissolved in enough water to make a 1.2-liter solution, what is the resulting molarity?

Svetradugi [14.3K]

Correct Answer: Option B i.e. 0.82 M 

Reason:
Given: number of moles of BaCl2 = 0.98, Volume of solution = 1.2 l

Molarity of solution = $\frac{\text{number of moles}}{\text{volume of solution (l)}}$ 
= $\frac{0.98}{1.21}$ 
= 0.82 M

Thus, molarity of the solution is 0.82 M

4 0

3 years ago

Read 2 more answers