180 is the totally amount it can be
Answer:
Step-by-step explanation:
You have the domain. It is given as -1≤x≤1
Now all you have to do is figure out the range which is the y value. At first glance I think it might be 3, but that does not look very logical. I'll post this much of it now and be back in under an hour with a more complete answer.
Of course! How silly of me. There is a minimum of y = 1 in the range which comes from x = 0
I've included a graph so you can see how this all works.
So the range = 1 ≤ y ≤ 3
Answer:
Mean = 30516.67
Standard deviation, s = 3996.55
P(x < 27000) = 0.0011518
Step-by-step explanation:
Given the data:
28500 35500 32600 36000 34000 25700 27500 29000 24600 31500 34500 26800
Mean, xbar = Σx / n = 366200 /12 = 30516.67
Standard deviation, s = [√Σ(x - xbar) / n-1]
Using calculator, s = 3996.55
The ZSCORE = (x - mean) / s/√n
Zscore = (27000 - 30516.67) / (3996.55/√12)
Zscore = - 3516.67 / 1153.7046
Zscore = - 3.048
P(x < 27000) = P(Z < - 3.049) = 0.0011518
<h3>
Answer: Choice B</h3>
With matrix subtraction, you simply subtract the corresponding values.
I like to think of it as if you had 2 buses. Each bus is a rectangle array of seats. Each seat would be a box where there's a number inside. Each seat is also labeled in a way so you can find it very quickly (eg: "seat C1" for row C, 1st seat on the very left). The rule is that you can only subtract values that are in the same seat between the two buses.
So in this case, we subtract the first upper left corner values 14 and 15 to get 14-15 = -1. The only answer that has this is choice B. So we can stop here if needed.
If we kept going then the other values would be...
row1,column2: P-R = -33-16 = -49
row1,column3: P-R = 28-(-24) = 52
row2,column1: P-R = 42-25 = 17
row2,column2: P-R = 35-(-30) = 65
row2,column3: P-R = -19-36 = -55
The values in bold correspond to the proper values shown in choice B.
As you can probably guess by now, matrix addition and subtraction is only possible if the two matrices are the same size (same number of rows, same number of columns). The matrices don't have to be square.
