All categories

3 years ago

How is temperature related to the physical change of a substance?

Chemistry

2 answers:

topjm [15]3 years ago

7 0

Answer:

Temperature is a measure of the kinetic energy of particles in a substance. As temperature increases, the atoms or molecules in a substance gain energy. As temperature decreases, the particles lose energy. A change in the energy of particles causes a change in their arrangement. A change in the arrangement of particles can lead to a physical change.

Explanation:

posledela3 years ago

4 0

Answer:

If the temperature gets low enough it may freeze or get frosty, and if it gets high enough it will melt or boil. The color may even change if it freezes or gets burnt, and the smell may change.

Explanation:

The temperature will affect the state, color, and even smell of a substance based on the substances' sensitivity to heat or cold.

You might be interested in

How many milliliters of 2.00 M H2SO4 will react with 28.0 g of NaOH?

77julia77 [94]

Answer:175⋅mL of the given sulfuric acid

Explanation:

5 0

3 years ago

Hydrogen peroxide decomposes to water and oxygen at constant pressure by the following reaction: 2H2O2(l) → 2H2O(l) + O2(g) ΔH =

ziro4ka [17]

Answer:

-8.64kJ

Explanation:

Based on the reaction:

2 H₂O₂(l) → 2 H₂O(l) + O₂(g) ΔH = -196 kJ

When 2 moles of hydrogen peroxide (H₂O₂) descomposed, there are released -196kJ of energy.

Now, if 3,00g of hydrogen peroxide react, moles are:

3.00g × (1mol / 34.01g) = 0.0882moles H₂O₂

Releasing:

0.0882moles H₂O₂ × (-196kJ / 2mol H₂O₂) = <em>-8.64kJ</em>

6 0

3 years ago

When the temperature is increased, what does not change?

gavmur [86]

Answer:

Pressure

Explanation:

They are both equal but do not change when the other does

3 0

3 years ago

For the reaction shown, identify the element oxidized, the element reduced, the oxidizing agent, and the reducing agent. KNO3 →

Vinvika [58]

Answer : The oxidizing element is N and reducing element is O.

$KNO_{3}$ is act as an oxidizing agent as well as reducing agent.

Explanation :

An Oxidizing agent is the agent which has ability to oxidize other or a higher in oxidation number.

Reducing agent is the agent which has ability to reduce other or lower in oxidation number.

The given reaction is :

$KNO_{3} \rightarrow KNO_{2} +O_{2}$

$KNO_{3}$ act as an oxidizing agent.

The oxidation number of N in $KNO_{3}$ is calculated as:

(+1)+(x)+3(-2) = 0

x = +5

And the oxidation number of N in $KNO_{2}$ is calculated as:

(+1)+(x)+2(-2) = 0

x = +3

From the oxidation number method, we conclude that the oxidation number reduced this means $KNO_{3}$ itself get reduced to $KNO_{2}$ and it can act as an oxidizing agent.

$KNO_{3}$ act as a reducing agent.

$KNO_{3} \rightarrow KNO_{2} +O_{2}$

The oxidation number of O in $KNO_{3}$ is calculated as:

(+1)+(+5)+3(x) = 0

x = -2

The oxidation number of O in $O_{2}$ is Zero (o).

Now, we conclude that the oxidation number increases this means $KNO_{3}$ itself get oxidized to $O_{2}$ and it can act as reducing agent.

4 0

4 years ago

Read 2 more answers

Find the solubility of agi in 2.5 m nh3 [ksp of agi = 8.3 × 10−17; kf of ag(nh3)2+ = 1.7 × 107].

vovangra [49]

When the first reaction equation is:

AgI(S) ↔ Ag+(Aq) + I-(Aq)

So, the Ksp expression = [Ag+][I-]

∴Ksp = [Ag+][I-] = 8.3 x 10^-17

Then the second reaction equation is:

Ag+(aq) + 2NH3(aq) ↔ Ag(NH3)2+

So, Kf expression = [Ag(NH3)2+] / [Ag+] [NH3]^2

∴Kf = [Ag(NH3)2+] /[Ag+] [NH3]^2 = 1.7 x 10^7

by combining the two equations and solve for Ag+:

and by using ICE table:

AgI(aq) + 2NH3 ↔ Ag(NH3)2+ + I-
initial 2.5 0 0

change -2X +X +X

Equ (2.5-2X) X X

so K = [Ag(NH3)2+] [I-] / [NH3]^2

Kf * Ksp = X^2 / (2.5-2X)

8.3 x 10^-17 * 1.7 x10^7 = X^2 / (2.5-2X) by solving for X

∴ X = 5.9 x 10^-5

∴ the solubility of AgI = X = 5.9 x 10^-5 M

4 0

3 years ago

How is temperature related to the physical change of a substance?​

How is temperature related to the physical change of a substance?