Number of particles inside a sugar bowl = 4.4 x 10²³
<h3>Further explanation</h3>
Given
The molar mass of sugar = 342.3 g/mol
mass of sugar = 250 g
Required
Number of particles
Solution
1 mol = 6.02 x 10²³ particles
mol of sugar :
![\tt mol=\dfrac{mass}{molar~mass}](https://tex.z-dn.net/?f=%5Ctt%20mol%3D%5Cdfrac%7Bmass%7D%7Bmolar~mass%7D)
mol = 250 g : 342.3 g/mol = 0.73 mol
Number of particles :
N = n x No
N = 0.73 x 6.02 x 10²³
N = 4.39 x 10²³ ≈ 4.4 x 10²³
Sugar, sucrose (C12H22O11: a disaccharide, composed of the two monosaccharides: glucose and fructose), is odorless, that is, it lacks odor. When heated a phase change occurs resulting in melting of a thick syrup.
Answer:
Ksp = [ Cu+² ] [ OH-] ²
molar mass Cu(oH )2 ==> M= 63.546 (1) + 16 (2) + 1 (2) = 97.546 g/mol
Ksp = [ Cu+² ] [ OH-] ²
Ksp [ cu (OH)2 ] = 2.2 × 10-²⁰
|__________|___<u>Cu</u><u>+</u><u>²</u><u> </u>__|_<u>2</u><u>OH</u><u>-</u>____|
|<u>Initial concentration(M</u>)|___<u>0</u>__|_<u>0</u>______|
<u>|Change in concentration(M)</u>|_<u>+S</u><u> </u>|__<u>+2S</u>__|
|<u>Equilibrium concentration(M)|</u><u>_S</u><u> </u><u>_</u><u>|</u><u>2S___</u><u>|</u>
Ksp = [ Cu+² ] [ OH-] ²
2.2 ×10-²⁰ = (S)(2S)²= 4S³
![s = \sqrt[3]{ \frac{2.2 \times {10}^{ - 20} }{4} } = 1.8 \times {10}^{ - 7}](https://tex.z-dn.net/?f=s%20%3D%20%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B2.2%20%5Ctimes%20%20%7B10%7D%5E%7B%20-%2020%7D%20%7D%7B4%7D%20%7D%20%20%3D%201.8%20%5Ctimes%20%20%7B10%7D%5E%7B%20-%207%7D%20)
S = 1.8 × 10-⁷ M
The molar solubility of Cu(OH)2 is 1.8 × 10-⁷ M
Solubility of Cu (OH)2 =
![Cu (OH)2 = \frac{1.8 \times {10}^{ - 7} mol \:Cu (OH)2 }{1L} \times \frac{97.546 \: g \: Cu (OH)2}{1 \: mol \: Cu (OH)2} \\ = 1.75428 \times 10 ^{ - 5}](https://tex.z-dn.net/?f=Cu%20%28OH%292%20%3D%20%20%5Cfrac%7B1.8%20%5Ctimes%20%20%7B10%7D%5E%7B%20-%207%7D%20mol%20%5C%3ACu%20%28OH%292%20%7D%7B1L%7D%20%20%5Ctimes%20%20%5Cfrac%7B97.546%20%5C%3A%20g%20%5C%3A%20Cu%20%28OH%292%7D%7B1%20%5C%3A%20mol%20%5C%3A%20Cu%20%28OH%292%7D%20%20%5C%5C%20%20%3D%201.75428%20%5Ctimes%2010%20%5E%7B%20-%205%7D%20)
<h3>
Solubility of Cu (OH)2 = 1.75428 × 10 -⁵ g/ L</h3>
I hope I helped you^_^
Answer:
Exposure of silver chloride to sunlight for a long duration turns grey due to photolytic decomposition i.e decomposition in the presence of sunlight.
Explanation:
When silver chloride, AgCl is exposed to sunlight for a long time, it will undergo decomposition as the sunlight provides sufficient energy needed to decomposed the salt, AgCl to metallic silver and chlorine gas. This can be seen in the equation below:
2AgCl —> 2Ag + Cl2