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Bas_tet [7]
2 years ago
13

What is the sum of the first 12 terms in the fibonacci sequence?

Mathematics
1 answer:
Neporo4naja [7]2 years ago
8 0
Hello,

u_{1} =a\\
 u_{2} =b\\
 u_{3} =a+b\\
 u_{4} =a+2b\\
 u_{5} =2a+3b\\
 u_{6} =3a+5b\\
 u_{7} =5a+8b\\
 u_{8} =8a+13b\\
 u_{9} =13a+21b\\
 u_{10} =21a+34b\\
 u_{11} =34a+55b\\
 u_{12} =55a+89b\\

\boxed{\sum_{i=1}^{12}(u_i)=144a+232b\\}





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Answer:

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Step-by-step explanation:

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2 years ago
In quadrilateral TUVW, m<U = 94º, m <V = 51°, and m<w =67º, what is m<T°?
Vlada [557]
The answer would be c) 129
4 0
3 years ago
In a previous​ year, 51​% of females aged 15 and older lived alone. A sociologist tests whether this percentage is different tod
Yanka [14]

Answer:

Given:

n = 550

Po = 51% = 0.51

P0 - 1 = 0.51 - 1 = 0.49

p' = \frac{287}{550} = 0.5218

np0(1 - p0) = 550*0.51(1-0.51)

= 137.4 ≥ 100

This means the sample size is greater than 5% of the population size. and the sample can be reasonably assumed to be random, the requirement for testing hypothesis are satisfied.

1) The null and alternative hypotheses:

H0 : p0 = 0.51

H1 : p0 ≠ 0.51

The test statistic Z,

Z = \frac{p' - p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}}

Z = \frac{0.5218 - 0.51}{\sqrt{\frac{0.51(1-0.51)}{550}}}

Z = 0.55

This is two tailed test.

The pvalue for Z =0.55

Pvalue = 0.5824

3) Decision:

Since pvalue, 0.5824 is greater than significance level, we fail to reject null hypothesis H0.

Conclusion:

Do not reject Upper H0. There is not sufficient evidence at the alpha equals 0.01 level of significance to conclude that the proportion of females who are living alone has changed.

8 0
3 years ago
Maya sells beaded necklaces. Each large necklace sells for $6.10 and each small necklace sells for $4.80 . How much will she ear
balandron [24]

Answer:

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Step-by-step explanation:

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7 0
2 years ago
Are the graphs y=4x-4 and 24x-4y=96 parallel
nydimaria [60]
k:y=m_1x+b_1;\ l:y=m_2x+b_2\\\\k\ ||\ l\iff m_1=m_2\\\\k:y=4x-4;\ l:24x-4y=96\\\\24x-4y=96\ \ \ \ |subtract\ 24x\ from\ both\ sides\\-4y=-24x+96\ \ \ \ |divide\ both\ sides\ by\ (-4)\\y=6x-24\\\\m_1=4;\ m_2=6\Rightarrow m_1\neq m_2

Answer: The graphs y = 4x - 4 and 24x - 4y = 96 are not parallel.
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2 years ago
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