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Bas_tet [7]
3 years ago
13

What is the sum of the first 12 terms in the fibonacci sequence?

Mathematics
1 answer:
Neporo4naja [7]3 years ago
8 0
Hello,

u_{1} =a\\
 u_{2} =b\\
 u_{3} =a+b\\
 u_{4} =a+2b\\
 u_{5} =2a+3b\\
 u_{6} =3a+5b\\
 u_{7} =5a+8b\\
 u_{8} =8a+13b\\
 u_{9} =13a+21b\\
 u_{10} =21a+34b\\
 u_{11} =34a+55b\\
 u_{12} =55a+89b\\

\boxed{\sum_{i=1}^{12}(u_i)=144a+232b\\}





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wlad13 [49]

The factor of the polynomial, the area of the pool and the simplified expression are all algebraic expressions

<h3>How to simplify the expressions?</h3>

<u>Factor of the polynomial</u>

The polynomial is given as:

2x^3 + 6x^2 + 6x + 18

Factor out 2

2x^3 + 6x^2 + 6x + 18 = 2(x^3 + 3x^2 + 3x + 9)

Factorize

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Factor out x + 3

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Expand

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<u>Simplify the expression</u>

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Read more about algebraic expressions at:

brainly.com/question/2164351

3 0
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Help asap please.. Brainliest to correct!
vovikov84 [41]

Answer:

Step-by-step explanation:

  x + 6 I x³ + 2x²  - 10x + 84   I   x² - 4x + 14

              x³ + 6x²

            <u> -     -       </u>

                     -4x² - 10x

                    -4x²  - 24x

                    <u> +       +     </u>

                               14x + 84

                                14x + 84

                               <u> -      -       </u>

                                     0

P(x)  =(x +6)* ( x² - 4x + 14) + 0

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