It will be Solvent the term that would describe the alcohol will be solvent.
Answer:
15.70mg would remain
Explanation:
Partition coefficient is used to extract or purify a solute from a solvent selectively to avoid interference from other substances. For the problem, formula is:
Kp = Concentration 9-fluorenone in ether / Concentration of solute in H₂O
After the solute, 9-fluorenone, is extracted with water, the mass that remains in ether is:
(19mg - X)
<em>Where X is the mass that now is in the aqueous phase</em>
Replacing in Kp formula:
9.5 = (19mg - X) / 5mL / (X /10mL)
0.95X = 19mg - X / 5mL
4.75X = 19 - X
5.75X = 19
X = 19 / 5.75
X = 3.30mg
That means 9-fluorenone that remain in the ether layer is:
19mg - 3.30mg =
<h3>15.70mg would remain</h3>
Answer: short answer short 0.65 / 5.37
15% NaOH by mass is 15g of NaOH in (100-15)g of solution.
No. Of moles of NaOH in solution = 0.65
No of moles of Water in solution = 4.72
Mole Fraction =
(
(Moles of Solvent)
(Moles Of Solute)+(Moles of Solvent)
)
OR
(
(Moles of Solvent)
Total Number Of Moles
)
= 0.65 / 5.37
= 0.121
Explanation:
Hope this helped
