Answer:
Sodium citrate is a compound with a total of 21 atoms
Increases with
hope this helped :))
correct me if i’m wrong
B is the answer I think hope this helps
Answer:


Explanation:
1 mol of nitrogen at STP = 22.4 L = 22400 cc
n = Mol of
= 
M = Molar mass of
= 
= Avogadro's number = 
Mass of
is

Mass of the nitrogen is 
Number of molecules is given by

The number of molecules present in it are 
Answer:
where is the answer options because it sounds like I need some