Bc it’s the only group that distinguishes amino acids from one another’s
Mass box C is 10+5. (So C is 15)
But if C was 30, how many times could you put B (5) into it?
30/5 = 6
You would need 6 boxes of B to make 30 grams of C.
24 molecules of H2O are needed by the plant to produce 4 molecules of sugar.
<h2>What is
photosynthesis?</h2>
The process by which plants convert carbon dioxide, water, and sunlight into oxygen and sugar-based energy is known as photosynthesis.
<h3>The photosynthesis equation is as follows:</h3>
6CO2 + 6H2O + Sunlight → C6H12O6 + 6O2
The following three significant activities are involved in photosynthesis:
1. Chlorophyll absorbs light energy.
2. Water molecules are divided into hydrogen and oxygen and light energy is converted to chemical energy.
3. Carbon dioxide is converted to sugars.
Therefore, a plant needs four molecules of H2O and four molecules of CO2 to make one molecule of glucose or sugar, hence a plant needs 24 molecules of H2O and 24 molecules of CO2 to make four molecules of sugar.
Learn more about photosynthesis here:
brainly.com/question/19160081
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Answer:
1. The balanced equation is given below:
C4H6O3 + H2O → 2C2H4O2
The coefficients are: 1, 1, 2
Explanation:
C4H6O3 + H2O → C2H4O2
The above equation can be balanced as follow:
There are 4 atoms of C on the left side and 2 atoms on the right side. It can be balance by putting 2 in front of C2H4 O2 as shown below:
C4H6O3 + H2O → 2C2H4O2
Now, the equation is balanced as the number of atoms of the different elements present on both sides of the equation are equal.
The coefficients are: 1, 1, 2
Answer:
Explanation:
Hello.
In this case, since the normal boiling point of X is 117.80 °C, the boiling point elevation constant is 1.48 °C*kg*mol⁻¹, the mass of X is 100 g and the boiling point of the mixture of X and KBr boils at 119.3 °C, we can use the following formula:
Whereas the Van't Hoff factor of KBr is 2 as it dissociates into potassium cations and bromide ions; it means that we can compute the molality of the solution:
Next, given the mass of solventin kg (0.1 kg from 100 g), we compute the moles KBr:
Finally, considering the molar mass of KBr (119 g/mol) we compute the mass that was dissolved:
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