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Tatiana [17]
3 years ago
9

Compounds A and B react to form compounds C and D according to the equation: aA + bB → cC + dD. Under which conditions will the

rate law be given by the equation: rate = k[A]a[B]b? A. The reaction takes place in one step. B. The reaction is endothermic. C. The reaction is exothermic. D. The reaction involves more than one step.
Chemistry
2 answers:
pantera1 [17]3 years ago
8 0

Answer:

anwer is a

Explanation:

Ipatiy [6.2K]3 years ago
5 0

Answer: A. The reaction takes place in one step.

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Molecularity of the reaction is defined as the number of atoms, ions or molecules that must colloid with one another simultaneously so as to result into a chemical reaction.

Order of the reaction is defined as the sum of the concentration of terms on which the rate of the reaction actually depends. It is the sum of the exponents of the molar concentration in the rate law expression.

Elementary reactions are defined as the reactions for which the order of the reaction is same as its molecularity and order with respect to each reactant is equal to its stoichiometric coefficient as represented in the balanced chemical reaction.

aA=bB\rightarrow cC+dD

Rate=k[A]^a[B]^b

k= rate constant

a= order with respect to A

b = order with respect to B

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Answer:

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Explanation:

Let's consider the following reaction.

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First, we will calculate the standard enthalpy of the reaction (ΔH°).

ΔH° = 1 mol × ΔH°f(CaO(s)) + 1 mol × ΔH°f(CO₂(g) ) - 1 mol × ΔH°f(CaCO₃(s) )

ΔH° = 1 mol × (-634.9 kJ/mol) + 1 mol × (-393.5 kJ/mol) - 1 mol × (-1207.6 kJ/mol)

ΔH° = 179.2 kJ

Then, we calculate the standard entropy of the reaction (ΔS°).

ΔS° = 1 mol × S°(CaO(s)) + 1 mol × S°(CO₂(g) ) - 1 mol × S°(CaCO₃(s) )

ΔS° = 1 mol × (38.1 J/mol.K) + 1 mol × (213.8 J/mol.K) - 1 mol × (91.7 J/mol.K)

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ΔG° = ΔH° - T × ΔS°

ΔG° = 179.2 kJ - 298 K × 0.1602 kJ/K

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