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Tatiana [17]
3 years ago
9

Compounds A and B react to form compounds C and D according to the equation: aA + bB → cC + dD. Under which conditions will the

rate law be given by the equation: rate = k[A]a[B]b? A. The reaction takes place in one step. B. The reaction is endothermic. C. The reaction is exothermic. D. The reaction involves more than one step.
Chemistry
2 answers:
pantera1 [17]3 years ago
8 0

Answer:

anwer is a

Explanation:

Ipatiy [6.2K]3 years ago
5 0

Answer: A. The reaction takes place in one step.

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Molecularity of the reaction is defined as the number of atoms, ions or molecules that must colloid with one another simultaneously so as to result into a chemical reaction.

Order of the reaction is defined as the sum of the concentration of terms on which the rate of the reaction actually depends. It is the sum of the exponents of the molar concentration in the rate law expression.

Elementary reactions are defined as the reactions for which the order of the reaction is same as its molecularity and order with respect to each reactant is equal to its stoichiometric coefficient as represented in the balanced chemical reaction.

aA=bB\rightarrow cC+dD

Rate=k[A]^a[B]^b

k= rate constant

a= order with respect to A

b = order with respect to B

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Answer:

<u> </u><u>85.952 ml</u> Zn^2^+  needed to titrate the excess complexing reagent .

Explanation:

Lets calculate

After addition of 80 ml of EDTA the solution becomes = 20 + 70 = 90 ml

As the number of moles of CoSO_4 =\frac{Given mass }{molar mass}

                                                       =\frac{1.817}{155}

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Molarity = \frac{no. of moles}{volume of solution}

           =\frac{0.01172}{20}

        =0.000586 moles

Excess of EDTA = concentration of EDTA - concentration of CoSO4

                            = 0.009005 - 0.000586

                           = 0.008419 M

As M1V1 ( Excess of EDTA ) = M2V2 (Zn^2^+)

           0.008419\times100ml=0.009795\times V2

           V2=\frac{0.008419\times100}{0.009795}

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Therefore , <u>85.952 ml </u>Zn^2^+ needed to titrate the excess complexing reagent .

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Explanation:

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plz mark brainliest

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