At the beginning, there are 15 pigs without ribbons. one of the pigs receives a ribbon. how many are left ribbonless?
<span>14. when another pig is given a ribbon, there are 13 left. after all the ribbons have been given out, 3 of the 15 pigs have ribbons. </span>
<span>if any one of the 15 at the beginning is given a ribbon, there are 15 possible combos. for the second ribbon, there are 14 combos- but each of those combos has to go through the first 15. for the third ribbon, there are 13 combos, going through 14 and 15. </span>
<span>simply put, 15 x 14 x 13.</span>
Answer: 165/11 =
(3 × 5 × 11)/11 =
((3 × 5 × 11) ÷ 11) / (11 ÷ 11) =
(3 × 5)/1 =
15/1 =
15
Step-by-step explanation:
What do you mean? 7 in 0.37 is 0.07 or 7 hundredths.
7 in 0.73 is 0.7 or 7 tenths?
Is that what you meant...
I'm not sure on this one but try .30 and .90 but don't count on it to much
Answer:
Below in bold letters.
Step-by-step explanation:
a. y = 3x - 1.
The equation of the perpendicular line will have slope -1/ 3.
So we have the equation y - y1 = -1/3(x - x1) where (x1, y1) is a point on this perpendicular line.
As the line passes through (0,0):
y - 0 = 1/3(x - 0)
y = -1/3x is the required equation.
If x,4 is on the line then x is found by substituting for y:
4 = -1/3 x
x = 4 / -1/3
x = 4*-3 = -12.
b. y = 1/4x + 2
By the same method as in part a:
the equation is y = -4x.
x = 4 / -4 = -1.
