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3 years ago

Which of these statements is correct regarding the location of glycolysis and cell respiration?

Biology

2 answers:

kobusy [5.1K]3 years ago

6 0

Answer: Option C

Explanation:

The process of glycolysis takes place in the cytoplasm of the cell. It converts glucose into pyruvate.

The free energy is released in this process to form high energy molecules know as ATP and NADH.

The process of cellular respiration takes place in the mitochondria where the energy is released in the form of ATP.

The energy from the food is converted into the form of ATP which is used by the body.

Bas_tet [7]3 years ago

4 0

Glycolysis occurs in the cytoplasm; Cell respiration occurs in the mitochondria.

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The f° -f^1 complex in the mitochondrial structure helps it

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Is norman bates and his mother the same person

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3 years ago

Which of the following samples will have the greatest volume at STP?a. 22 g Neb. 22 g Hec. 22 g O2d. 22 g Cl2 e. All have the sa

sammy [17]

Answer:

22g of He

Explanation:

Volume of gas at STP is given as :

Volume occupied(dm³) = number of moles x 22.4dm³mol⁻¹

In order to solve this given problem, we would first find the number of moles from the different masses of atoms and molecules given.

Number of moles = $\frac{mass }{Molar mass}$

Now, let us obtain the molar mass of the given atoms and elements:

For Ne; molar mass is the atomic mass = 20gmol⁻¹

He = 4gmol⁻¹

O₂ = (16 x2)gmol⁻¹ = 32gmol⁻¹

Cl₂ = (35.5x2)gmol⁻¹ = 71gmol⁻¹

Number of moles of Ne = $\frac{22}{20}$ = 1.1mol

Volume occupied by Ne at STP = 1.1 x 22.4 = 24.64dm³

Number of moles of He = $\frac{22}{4}$ = 5.5mol

Volume occupied by He at STP = 5.5 x 22.4 = 123.2dm³

Number of moles of O₂ = $\frac{22}{32}$ = 0.688mol

Volume occupied by O₂ at STP = 0.688 x 22.4 = 15.4mol

Number of moles of Cl₂ = $\frac{22}{71}$ = 0.3099mol

Volume occupied by Cl₂ at STP = 0.3099 x 22.4 = 6.94dm³

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3 years ago

A researcher is investigating two species of fungi, fungus X and fungus Y. The characteristics of each fungus are given in the t

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The correct answer is: B. Fungus X is a common mold, and fungus Y is a chytrid.

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Chytrid ("little pot") refers to group of fungi with chitin cell walls, a posterior flagellum and absorptive nutrition. They reproduce with zoospores (motile asexual spores).

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3 years ago