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siniylev [52]
3 years ago
5

What is the area of a triangle whose sides are 15 cm, 8 cm and 19 cm?​

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
3 0
Is it 2,280
Hope that work
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33 because it is talking about the hours
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3 years ago
The sum of 3 consecutive numbers is 99 what are the numbers ​
Vera_Pavlovna [14]

Answer:

32+33+34

Step-by-step explanation:

If I understand the question correctly, you're looking for 3 different numbers that are all consecutive that add up to be 99. The way I did it was finding 3 consecutive numbers that add to 9. 2, 3, 4. I knew the 10s place had to be a 3 because 30+30+30=90, 2+3+4=9, 90+9=99

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b) if your friend wants to be as happy as possible, how many cheeseburgers should he eat? How do you know ? Answer question B
Svetllana [295]

Answer:

Find out what x should be the apply by the power of 2 then you should be good

7 0
3 years ago
Given the following diagram, find the measures of ZA and ZB.
Nutka1998 [239]

Answer:

x = 14.6

ZA = 30.8

ZB = 33.2

Step-by-step explanation:

First, solve x: (knowing all angles of a triangle are 180º)

116º + (2x + 4)º + (3x-13)º = 180º

116 + 2x + 4 + 3x - 13 = 180

2x + 3x = 180 + 13 - 4 - 116

5x = 73

x = 73/5 = 14.6

ZA = 3*14.6 - 13 = 30.8

ZB = 2*14.6 + 4 =33.2

Test:

116º + 33.2º + 30.8º = 180º

3 0
3 years ago
Read 2 more answers
Explain why any of the four operations placed between two terms 5 and -3 sqrt (8) will result in an irrational number
Gnoma [55]

Sum/difference:

Let

x = 5 + (-3\sqrt{8}) = 5-3\sqrt{8}

This means that

3\sqrt{8} = 5-x \iff \sqrt{8} = \dfrac{5-x}{3}

Now, assume that x is rational. The sum/difference of two rational numbers is still rational (so 5-x is rational), and the division by 3 doesn't change this. So, you have that the square root of 8 equals a rational number, which is false. The mistake must have been supposing that x was rational, which proves that the sum/difference of the two given terms was irrational

Multiplication/division:

The logic is actually the same: if we multiply the two terms we get

x = -15\sqrt{8}

if again we assume x to be rational, we have

\sqrt{8} = -\dfrac{x}{15}

But if x is rational, so is -x/15, and again we come to a contradiction: we have the square root of 8 on one side, which is irrational, and -x/15 on the other, which is rational. So, again, x must have been irrational. You can prove the same claim for the division in a totally similar fashion.

7 0
3 years ago
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