Answer:
-2x+2y+3z=0
-2x-y+z=-3
2x+3y+3z=5
---------------
-2x+2y+3z=0
-2x-y+z=-3
---------------- Subtract
3y + 2z = 3 Eqn A
=========================
-2x-y+z=-3
2x+3y+3z=5
---------------- Add
2y + 4z = 2
6y + 4z = 6 Eqn A times 2
------------------------------------ Subtract
-4y = -4
y = 1
-----------------
z = 0
-------------------
x = 1
Answer:
yes no
no yes
no yes
Step-by-step explanation:
Answer:
I don't know how to insert a number line, but you have to put on it x<-3. You have to plot it, then put a open circle at -3, and draw an arrow, pointing it farther into the negitive side of the number line.
Step-by-step explanation:
Answer:
"i". There's no more than that. Its just "i".
Step-by-step explanation:
Answer:
Period of the function is 4π
Step-by-step explanation:
Given is a graph:
It oscillates between -1 and +1
The graph shows angles on x axis and trig values on y axis.
The graph has value +1 when x=0 and reaches minimum -1 when x =2pi and again reaches y=1 when x =4 π
Thus we find that this is a periodic function with amplitude 1 and phase shift 0 and period 4π
So we get the period of the trignometric funciton is 4π
So option 1 is right
Verify:
Given function is y = cos
Since parent function y =cosx has a period of 2pi, we have
here period = 2pi/coefficient of x in cos
=2pi/(1/2)
=4pi