Question

Calculate the volume occupied by 0.845 mole of nitrogen gas, the pressure, and the temperature. Find the volume.

Answer 1

Answer:

V = 15.9512 dm³

Explanation:

Given data:

Pressure = P = 1.37 atm

Temperature = T= 315 K

Number of moles of nitrogen= n = 0.845 mol

Volume = V = ?

Formula:

PV = nRT

Now we will put the values in equation.

V = nRT/ P

V = ( 0.845 mol× 0.0821 dm³.atm.K⁻¹.mol⁻¹ × 315 K) / 1.37 atm

V = 21.853 dm³. atm/  1.37 atm

V = 15.9512 dm³

Answer 2

Answer:

The volume occupied by 0.845 mole of nitrogen gas is 15.9 L.

Explanation:

Given

N = 0.845 mol

P = 1.37 atm

T = 315 k

We make use of the Ideal gas equation to solve this problem

Ideal gas law equation is

PV=nRT

Rearranging the formula                  

$v= \frac {nRT}{V}$

Plugging in the values given we have

$v=\frac {(0.845mol \times 0.08206 L atmk^{-1} mol^{-1} \times 315K)}{1.37atm}$

v = 15.9 L is the volume occupied by 0.845 mole of nitrogen gas.