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Mrrafil [7]
2 years ago
11

Which two factors that influence weather are caused by the uneven heating of

Chemistry
2 answers:
just olya [345]2 years ago
8 0
B, sorry if i am wrong.
Alex2 years ago
7 0
I guess it C. The formation of convection currents in the atmosphere
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Unit 2 | Lesson 7
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Eukaryotic celss have organelles which perform specific functions
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3 years ago
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Based on the kinetic molecular theory, which of the following statements is correct about the particles in a sample of gas at a
fgiga [73]

Answer:

There is a lot of empty space between them.

Explanation:

The kinetic molecular theory postulates that a substance is made up of tiny particles called molecules. The molecules of a gas are in constant random motion and collide elastically with each other. They also collide with the walls of the container.

The magnitude of intermolecular forces of attraction between gas molecules is very small. Hence gas molecules are largely apart with a lot of empty space between gas molecules.

8 0
3 years ago
I need an analysis and conclusion, for the lab, Types of reactions
Leya [2.2K]

Answer:

Explanation:

I am a bit confused is there instuctions on what to write on or anything like that

3 0
3 years ago
CaCO3(s) ⇄ CaO(s) + CO2(g) 0.100 mol of CaCO3 and 0.100 mol CaO are placed in an 10.0 L evacuated container and heated to 385 K.
Montano1993 [528]

Answer:

The final mass of CaCO3 is 10.68 grams

Explanation:

Step 1: Data given

Number of moles CaCO3 = 0.100 moles

Number of moles CaO = 0.100 moles

Volume = 10.0 L

When equilibrium is reached the pressure of CO2 is 0.220 atm. 0.250 atm of CO2 is added, while keeping the temperature constant

Step 2: The balanced equation

CaCO3(s) <==> CaO(s) + CO2(g)

Step 3: Calculate moles of CO2

n = PV/RT

⇒n = the initial number of moles CO2 = TO BE DETERMINED

⇒P = the pressure of CO2 at theequilibrium = 0.220 atm

⇒V = the volume of the container = 7.0 L

⇒R = the gas constant = 0.08206 L*atm / mol * K

⇒T = the temperature = 385 K

n = 0.220*7.0/(0.08206*385) = 0.0487 (mol)

this is the amount of CaCO3 which has been converted to CaO before pumping-in additional 0.225 atm CO2(g).

Step 4: Calculate moles CaCO3

After adding additional 0.250 atm CO2(g), the equilibrium CO2 pressure is still 0.220 atm.  All this additional CO2 would completely convert to CaCO3:

n = PV/RT = 0.250*7.0/(0.08206*385) = 0.0554 moles

The total CaCO3 after equilibrium is reestablished is:

0.100 - 0.0487+ 0.0554 = 0.1067 mol

Step 5: Calculate mass CaCO3

Mass CaCO3 = 0.1067 moles * 100.09 g/mol

Mass CaCO3 = 10.68 grams

The final mass of CaCO3 is 10.68 grams

8 0
3 years ago
S + 6 HNO3 --&gt; H2SO4 + 6 NO2 + 2 H2O
lina2011 [118]

Answer:

43.5 moles of HNO₃.

Explanation:

The balanced equation for the reaction is given below:

S + 6HNO₃ —> H₂SO₄ + 6NO₂ + 2H₂O

From the balanced equation above,

6 moles of HNO₃ reacted to produce 2 moles of H₂O.

Finally, we shall determine the number of mole of HNO₃ required to produce 14.5 moles of H₂O.

This can be obtained as illustrated below:

From the balanced equation above,

6 moles of HNO₃ reacted to produce 2 moles of H₂O.

Therefore, Xmol of HNO₃ will react to produce 14.5 moles of H₂O i.e

Xmol of HNO₃ = (6 × 14.5)/2

Xmol of HNO₃ = 43.5 moles

Therefore, 43.5 moles of HNO₃ is required to produce 14.5 moles of H₂O.

7 0
2 years ago
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