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aev [14]
3 years ago
13

Which reactions are single displacement reactions? 2NaBr + CaF2 → 2NaF + CaBr2 SnO2 + 2H2 → Sn + 2H2O 4Na + O2 → 2Na2O 2KClO3 →

2KCl + 3O2 2Al + 6HCl → 2AlCl3 + 3H2
Chemistry
1 answer:
r-ruslan [8.4K]3 years ago
5 0

Answer : The correct options are, SnO_2+2H_2\rightarrow Sn+2H_2O and 2Al+6HCl\rightarrow 2AlCl_3+3H_2

Explanation :

Single displacement reaction : It is a type of chemical reaction in which the more reactive element displaces the less reactive element.

Option A reaction : 2NaBr+CaF_2\rightarrow 2NaF+CaBr_2

It is an example of double displacement reaction because in this reaction a positive cation and a negative anion of the two reactants exchange their places to form two new products.

Option B reaction : SnO_2+2H_2\rightarrow Sn+2H_2O

It is an example of single displacement reaction.

Option C reaction : 4Na+O_2\rightarrow 2Na_2O

It is an example of combination reaction because in this reaction two reactants react to give a single product.

Option D reaction : 2KClO_3\rightarrow 2KCl+3O_2

It is an example of decomposition reaction because in this reaction a single reactant decomposes into two or more products.

Option E reaction : 2Al+6HCl\rightarrow 2AlCl_3+3H_2

It is an example of single displacement reaction because in this reaction the most react element, aluminium displaces the less reactive element, hydrogen.

Hence, the options B and E are single displacement reactions.

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Zn + 2HCl ---> ZnCl2 + H2 1. Is the equation above balanced or unbalanced? How do you know? (Hint: How many atoms of each typ
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The combustion of hydrogen-oxygen mixtures is used to produce very high temperatures (ca. 2500 °C) needed for certain types of w
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Answer:

1360kJ are evolved

Explanation:

When 1mole of H2 reacts with 1/2 moles O2 producing 1 mole of water and 241.8kJ.

To solve this question we need to find the limiting reactant knowing were added 90g of H2 and 90g of O2 as follows:

<em>Moles H2 -Molar mass: 2g/mol-</em>

90g H2 * (1mol / 2g) = 45 moles

<em>Moles O2 -Molar mass: 32g/mol-</em>

90g * (1mol / 32g) = 2.81moles

For a complete reaction of 2.81 moles of O2 are needed:

2.81 moles O2 * (1mol H2 / 1/2 mol O2) = 5.62 moles H2

As there are 45 moles, H2 is the excess reactant and O2 the limiting reactant.

As 1/2 moles O2 produce 241.8kJ, 2.81 moles will produce:

2.81 moles O2 * (241.8kJ / 1/2moles O2) =

<h3>1360kJ are evolved</h3>
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