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aev [14]
3 years ago
13

Which reactions are single displacement reactions? 2NaBr + CaF2 → 2NaF + CaBr2 SnO2 + 2H2 → Sn + 2H2O 4Na + O2 → 2Na2O 2KClO3 →

2KCl + 3O2 2Al + 6HCl → 2AlCl3 + 3H2
Chemistry
1 answer:
r-ruslan [8.4K]3 years ago
5 0

Answer : The correct options are, SnO_2+2H_2\rightarrow Sn+2H_2O and 2Al+6HCl\rightarrow 2AlCl_3+3H_2

Explanation :

Single displacement reaction : It is a type of chemical reaction in which the more reactive element displaces the less reactive element.

Option A reaction : 2NaBr+CaF_2\rightarrow 2NaF+CaBr_2

It is an example of double displacement reaction because in this reaction a positive cation and a negative anion of the two reactants exchange their places to form two new products.

Option B reaction : SnO_2+2H_2\rightarrow Sn+2H_2O

It is an example of single displacement reaction.

Option C reaction : 4Na+O_2\rightarrow 2Na_2O

It is an example of combination reaction because in this reaction two reactants react to give a single product.

Option D reaction : 2KClO_3\rightarrow 2KCl+3O_2

It is an example of decomposition reaction because in this reaction a single reactant decomposes into two or more products.

Option E reaction : 2Al+6HCl\rightarrow 2AlCl_3+3H_2

It is an example of single displacement reaction because in this reaction the most react element, aluminium displaces the less reactive element, hydrogen.

Hence, the options B and E are single displacement reactions.

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From E=mc²=hv show that wavelength=h/mv​
barxatty [35]

Explanation:

To show - from E=mc²=hv show that wavelength=h/mv​

Proof -

Given that,

E = mc²

E = hν

By equating both the equations, we get

mc² = hν

Because real particles do not travel at the speed of light, De Broglie submitted velocity ( v ) for the speed of light ( c ).

mv² = hν

Through the equation  λ , de Broglie substituted  v/λ  for  ν  and arrived at the final expression that relates wavelength and particle with speed.

mv² = hv/λ

⇒λ = hv/mv²

⇒λ = h/mv

Hence showed.

8 0
3 years ago
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ANTONII [103]

Answer:The equilibrium constant for a given reaction is [concentration of products]/[concentration of reactants].

Explanation:

Equilibrium constant=[concentration of products]/[concentration of reactants]

The concentration of reactant  molecules is maximum at time 0 and it  decreases as the reaction proceeds, The concentration of product molecules increases.At equilibrium the concentration of reactants and products are equal.

All the changes would occur in accordance with the LeChateliers principle.

For the given reaction the following changes would occur:

a When CO is removed from the reaction mixture so the reaction would shift towards right that is in forward direction as we are decreasing the concentration of CO so the system would try to increase the concentration of CO and that can happen by more production of CO.

b Since the above reaction is an endothermic reaction so when we would be adding heat to the system that is when we would increase the temperature  the reaction would shift forwards as  more heat energy is absorbed by reactants  to form more products.

c When more CO₂ is added so more amount of reactants are added to the system so the system would try to decrease the amount of reactants that is CO₂ and hence more amount of products would be formed.The reaction would shift in forward direction.

d Since  this reaction is endothermic in nature so when we remove the heat from reaction hence even less amount of heat is present in the system and so the reaction shift in backward direction as the reaction cannot proceed without enough amount of heat.

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Answer:

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Explanation:

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The PbO obtained is reduced by charcoal(C) to obtain the metallic Pb as shown below:

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