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Aleksandr-060686 [28]
3 years ago
8

Which kind of energy is greater? Potential or kinetic energy?

Physics
2 answers:
Nataly_w [17]3 years ago
5 0

Answer: it depends potential energy is the build up of kinetic energy like going to the top of a roller coaster. kintic is the use of the potential energy like going down the roller coaster so depends how much energy one another give :)

Hope this helps you out :)

olasank [31]3 years ago
3 0

Answer:

Explanation:

The question has no set meaning. Suppose you take a rock to the top of a building. You put the rock over the edge of the building. You don't drop it yet. The potential energy is greatest for the rock under this condition. The kinetic energy is 0 because the rock is not moving.

Now you let the rock go. As it falls, it looses distance to the ground which means that the Potential energy is nearing 0. The Kinetic energy is picking up because the rock is moving faster.

At the bottom of the rock's journey just before it hits the ground, the KE is at a maximum and the PE is nearly 0.

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Many types of scientific equipment are used to perform different functions in the science lab.Which of the folllowing combinatio
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Answer:

Many types of scientific equipment are used to perform different functions in the science lab. Which of the following combinations of equipment would be needed to bring one liter of water to 85°C? a. ... Various pieces of safety equipment are used in the lab to provide protection against injury.

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3 years ago
Observe the given figure and find the the gravitational force between m1 and m2.​
Leno4ka [110]

Answer:

The gravitational force between m₁ and m₂, is approximately 1.06789 × 10⁻⁶ N

Explanation:

The details of the given masses having gravitational attractive force between them are;

m₁ = 20 kg, r₁ = 10 cm = 0.1 m, m₂ = 50 kg, and r₂ = 15 cm = 0.15 m

The gravitational force between m₁ and m₂ is given by Newton's Law of gravitation as follows;

F =G \cdot \dfrac{m_{1} \cdot m_{2}}{r^{2}}

Where;

F = The gravitational force between m₁ and m₂

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

r₂ = 0.1 m + 0.15 m = 0.25 m

Therefore, we have;

F = 6.67430 \times 10^{-11} \ N \cdot m^2/kg \times \dfrac{20 \ kg\times 50 \ kg}{(0.1 \ m+ 0.15 \ m)^{2}} \approx 1.06789 \times 10^{-6} \ N

The gravitational force between m₁ and m₂, F ≈ 1.06789 × 10⁻⁶ N

8 0
2 years ago
a force 2.4E2 N exists between a positive charge of 8E-5 C and a positive charge of 3E-5 C. What distance separates the charges?
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The distance between the two charges is 0.3 m

Explanation:

The electrostatic force between two charged objects is given by Coulomb's law:

F=k\frac{q_1 q_2}{r^2}

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k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q_1, q_2 are the charges of the two objects

r is the separation between the two charges

In this problem, we are given the following:

q_1 = 8\cdot 10^{-5} C

q_2 = 3\cdot 10^{-5} C

F=2.4\cdot 10^2 N

Therefore, we can rearrange the equation to solve for r, the distance between the two charges:

r=\sqrt{\frac{kq_1 q_2}{F}}=\sqrt{\frac{(8.99\cdot 10^9)(8\cdot 10^{-5})(3\cdot 10^{-5})}{2.4\cdot 10^2}}=0.3 m

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