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3 years ago

Which kind of energy is greater? Potential or kinetic energy?

2 answers:

5 0

Answer: it depends potential energy is the build up of kinetic energy like going to the top of a roller coaster. kintic is the use of the potential energy like going down the roller coaster so depends how much energy one another give :)

Hope this helps you out :)

olasank [31]3 years ago

3 0

Answer:

Explanation:

The question has no set meaning. Suppose you take a rock to the top of a building. You put the rock over the edge of the building. You don't drop it yet. The potential energy is greatest for the rock under this condition. The kinetic energy is 0 because the rock is not moving.

Now you let the rock go. As it falls, it looses distance to the ground which means that the Potential energy is nearing 0. The Kinetic energy is picking up because the rock is moving faster.

At the bottom of the rock's journey just before it hits the ground, the KE is at a maximum and the PE is nearly 0.

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1 year ago

Suppose a straight 1.00-mm-diameter copper wire could just "float" horizontally in air because of the force due to the Earth’s m

insens350 [35]

To solve this problem it is necessary to apply the concepts related to the Force since Newton's second law, as well as the concept of Electromagnetic Force. The relationship of the two equations will allow us to find the magnetic field through the geometric relations of density and volume.

$F_{mag}= BIL$

Where,

B = Magnetic Field

I = Current

L = Length

<em>Note: $F_{mag}$ is a direct adaptation of the vector relation $F=q \times V \times B$ </em>

From Newton's second law we know that the relation of Strength and weight is determined as

$F_g = mg$

Where,

m = Mass

g = Gravitational Acceleration

For there to be balance the two forces must be equal therefore

$F_{mag} = F_g$

$BIL = mg$

Our values are given as,

Diameter $(d) = 1.0mm = 1*10^{-3}m$

Radius $(r) = \frac{d}{2} = \frac{1*10^{-3}}{2} = 0.5*10^{-3}m$

Magnetic Field $(B) = 5.0*10^{-5} T$

From the relationship of density another way of expressing mass would be

$\rho = \frac{m}{V} \rightarrow m = \rho V$

At the same time the volume ratio for a cylinder (the shape of the wire) would be

$V = \pi r^2 L \rightarrow L =Length, r= Radius$

Replacing this two expression at our first equation we have that:

$BIL = mg$

$BIL = ( \rho V)g$

$BIL = ( \rho \pi r^2 L)g$

Re-arrange to find I

$I = \frac{( \rho \pi r^2 L)g}{BL}$

$I = \frac{( \rho \pi r^2 )g}{B}$

We have for definition that the Density of copper is $8.9*10^3 Kg/m^3$ , gravity acceleration is $9.8m/s^2$ and the values of magnetic field (B) and the radius were previously given, then: