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zimovet [89]
3 years ago
5

When flying the LNAV approach, the missed approach point (MAP) would be indicated by reaching __________. A. an altitude of 3100

feet.B. a distance of 1.5 NM to RW30.C. the RW30 waypoint.
Physics
1 answer:
frutty [35]3 years ago
8 0

Answer:

When flying the LNAV Approach, the missed approach point (MAP) would be indicated by reaching:

C. the RW30 waypoint.

Explanation:

  • In Aviation, LNAV stands for Lateral Navigation. The option a is incorrect as an altitude of 3100 feet refers to the decision altitude not the missed approach point.
  • The option b is incorrect as a distance of 1.5 NM  to RW30 referring to the Visual descent point (VDP) is 1.5 nautical miles for the Runway (RW) 30 from threshold.
  • The option c is correct as Missed approach point is designed to coincide with the runway threshold. The RW 30 way point is referring to the way point to the threshold for the Runway 30.

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A proton is initially at rest. After some time, a uniform electric field is turned on and the proton accelerates. The magnitude
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a) 8.83*10⁵ m/s  b) 2.80*10⁶ m/s

Explanation:

a) Assuming no other forces acting on the proton, the acceleration on it is produced by the electric field.

By definition, the  force due to the electric field is as follows:

F = q*E = e*E (1)

where e is the elementary charge, the charge carried by only one proton, and is e = 1.6*10⁻¹⁹ C.

According to Newton's 2nd law, this force is at the same time, the product of the mass of the proton, times the acceleration a:

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From (1) and(2), being left sides equal, right sides must be equal too:

F = e*E = mp*a

Solving for a:

a = \frac{e*E}{mp} =\frac{1.6e-19C*1.36e5N/C}{1.67e-27kg} =1.3e13 m/s2

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As we have the value of a (which is constant due to the field is uniform), the displacement x, and we know that the initial velocity is 0, in order to get the value of the speed, we can use the following kinematic equation:

vf^{2} -vo^{2} = 2*a*x

Replacing by v₀ = 0, a= 1.3*10¹³ m/s² and  x = 0.03 m, we can find vf as follows:

vf =\sqrt{2*(1.3e13 m/s2)*0.03m} = 8.83e5 m/s

⇒ vf = 8.83*10⁵ m/s

b) We can just repeat the equation from above, replacing x=0.03 m by x=0.3 m, as follows:

vf =\sqrt{2*(1.3e13 m/s2)*0.3m} = 2.80e6 m/s

⇒ vf = 2.80*10⁶ m/s

4 0
3 years ago
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