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cestrela7 [59]
2 years ago
7

I’m stuck on this problem, help is very appreciated!!

Physics
2 answers:
yaroslaw [1]2 years ago
8 0

Explanation:

Use the equation F=m×a

F= 1500 N

M= 500kg

a= F/M

a= 1500÷ 500

a= 3m/s^2

Marta_Voda [28]2 years ago
5 0

Answer:

Explanation:

Force, f = 1500 N

Mass, m = 500 kg

Acceleration, a = ?

f = ma

a = f/m

= 1500 / 500 = <u><em>3m/s^2</em></u>

Hope this helps

plz mark as brainliest!!!!!

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Which is likely to be more common in our Galaxy: white dwarfs or black holes? Why?
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Answer:

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2 years ago
The earth's radius is 6.37×106m; it rotates once every 24 hours.What is the speed of a point on the earth's surface located at 3
bagirrra123 [75]

Answer:

v = 120 m/s

Explanation:

We are given;

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Angular speed; ω = 2π/(24 × 3600) = 7.27 × 10^(-5) rad/s

Now, we want to find the speed of a point on the earth's surface located at 3/4 of the length of the arc between the equator and the pole, measured from equator.

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θ = ¾ × 90

θ = 67.5

¾ is multiplied by 90° because the angular distance from the pole is 90 degrees.

The speed of a point on the earth's surface located at 3/4 of the length of the arc between the equator and the pole, measured from equator will be:

v = r(cos θ) × ω

v = 6.37 × 10^(6) × cos 67.5 × 7.27 × 10^(-5)

v = 117.22 m/s

Approximation to 2 sig. figures gives;

v = 120 m/s

8 0
3 years ago
Rosa listed some advantages and disadvantages of using renewable resources. Which best describes Rosa’s error?
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</span><span>
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5 0
3 years ago
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A particle moves along the x axis. It is initially at the position 0.180 m, moving with velocity 0.060 m/s and acceleration -0.3
shusha [124]

Answer:

a

  x_2 = -2.3356

b

 v = -1.384 \ m/s

Explanation:

From the question we are told that

  The initial position of the particle is  x_1 = 0.180 \ m

  The initial  velocity of the particle is  u = 0.060  \  m/s

  The acceleration is   a = -0.380 \  m/s^2

   The time duration is  t = 3.80  \ s

Generally from kinematic equation

    v = u + at

=>  v = 0.060 + (-0.380 * 3.80)

=>  v = -1.384 \ m/s

Generally from kinematic equation

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Here s is the distance covered by the particle, so

   (-1.384)^2 = (0.060)^2 + 2(-0.380)* s

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=>   x_2 = -2.3356

6 0
2 years ago
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