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3 years ago

Which diagram best represents the field around a positively charged particle?

Physics

1 answer:

AveGali [126]3 years ago

6 0

The last one. Opposites attract while similar ones repulse each other so all forces are pushing them apart

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6. A lumberjack is standing on a log floating on a lake. She starts from rest, then runs along the log to the end, when she jump

scoray [572]

Answer:

a) -3.267 m/s

b) 2.227 m/s

Explanation:

As per the conservation of momentum

m1v1 + m2v2=0

m1= mass of log

m2 = mass of lumber jack

v1 = velocity of log

v2 = velocity of lumber jack

a) Velocity of first log

$-\frac{70*7}{150} = -3.267$ m/s

b) m1v1 + m2v2 = m3v3

Velocity of log

= $\frac{70*7}{150+70} \\2.227$

4 0

3 years ago

What is the gravitational potential energy of a 0.1 kg apple sitting on top of a 12.5 m flagpole? Note: GPE= mgh. m= mass, g= ac

Pachacha [2.7K]

GPE= mgh = 0.1 kg * 9.8 m/s^2 * 12.5m = 12.25 J

6 0

3 years ago

Choose the word that best completes each sentence.

Igoryamba

Answer:

1.) Tropisms

2.) Thigmotropism

3.) Phototropism

4 0

3 years ago

Read 2 more answers

How much does the Earth weigh? Have an AWESOME day -NaomiTheGenuis

babymother [125]

Answer:

The Earth weighs about:
13,170,000,000,000,000,000,000,000 pounds

or

5.97 billion trillion metric tons

Explanation:

Have a great rest of your day
#TheWizzer

3 0

2 years ago

Read 2 more answers

At t=0 bullet A is fired vertically with an initial (muzzle) velocity of 450 m/s. When 3s. bullet B is fired upward with a muzzl

Debora [2.8K]

Answer:

At time 10.28 s after A is fired bullet B passes A.

Passing of B occurs at 4108.31 height.

Explanation:

Let h be the height at which this occurs and t be the time after second bullet fires.

Distance traveled by first bullet can be calculated using equation of motion

$s=ut+0.5at^2 \\$

Here s = h,u = 450m/s a = -g and t = t+3

Substituting

$h=450(t+3)-0.5\times 9.81\times (t+3)^2=450t+1350-4.9t^2-29.4t-44.1\\\\h=420.6t-4.9t^2+1305.9$

Distance traveled by second bullet

Here s = h,u = 600m/s a = -g and t = t

Substituting

$h=600t-0.5\times 9.81\times t^2=600t-4.9t^2\\\\h=600t-4.9t^2 \\$

Solving both equations

$600t-4.9t^2=420.6t-4.9t^2+1305.9\\\\179.4t=1305.9\\\\t=7.28s \\$

So at time 10.28 s after A is fired bullet B passes A.

Height at t = 7.28 s

$h=600\times 7.28-4.9\times 7.28^2\\\\h=4108.31m \\$

Passing of B occurs at 4108.31 height.

6 0

3 years ago