Answer:
see explanation
Explanation:
Given quantities:
radius = r = 0.0558 [m]
current = I = 0.23 [A]
Now we solve this by obtaining the torque acting on the dipole
We obtain the magnetic moment vector M, first, |M| is defined as , where A is the cross-section area of the loop which is
then
now the magnetic moment vector is equal to the magnetic dipole moment vector multiplied the magnitude we just obtained
Now:
a )
b)
a) the determinant gives us:
b) the dot product gives =
Answer:
Both
A. Low tides are lowest at both full moon and new moon.
B. High tides are highest at both full moon and new moon.
Explanation:
Tides are formed as a consequence of the differentiation of gravity due to the moon across to the Earth sphere.
Since gravity variate with the distance:
(1)
Where m1 and m2 are the masses of the two objects that are interacting and r is the distance Where m1 and m2 are the masses of the two objects that are interacting and r is the distance between them.
For example, see the image below, point A is closer to the moon than point b and at the same time the center of mass of the Earth will feel more attracted to the moon than point B. Therefore, that creates a tidal bulge in point A and point B.
On the other hand, a full moon it gets when Sun, the Earth and the moon are in a line and the moon is reflecting the sunlight.
When the Moon is between the Earth and the Sun it will be illuminated in its back, so it is not possible to see it from the Earth (that is called new moon).
In those two cases mentioned above, the Sun tidal force contributes to the tidal force of the moon over the earth making high tides higher and low tides lower.
