1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vitek1552 [10]
3 years ago
14

NaOH + HCl → NaCl + H2O

Chemistry
2 answers:
andreev551 [17]3 years ago
7 0

Answer:

B) use 0.2 M HCl

Explanation:

Lowering the concentration of a reactant will slow down the rate of reaction. If she would use 0.2 M HCl, the reaction rate will be slower than with 1.0 M HCl. The other choices would increase the rate of reaction, making it even more dangerous.

Rudik [331]3 years ago
6 0

The correct answer is B).

You might be interested in
If 2 objects have the same density they must have the same
atroni [7]

Answer:

Explanation:

Density can be defined as mass divided by volume. But 2 objects made of the same material will have the same density regardless of their volume.

8 0
3 years ago
2C2H6(g) + 7O2(g) → 4CO2(g) + 6H2O(g)
Ket [755]

Answer:- 10 L of ethane.

Solution:- The given balanced equation is:

2C_2H_6(g)+7O_2(g)\rightarrow 4CO_2(g)+6H_2O(g)

From this equation, ethane and oxygen react in 2:7 mol ratio, the ratio of volumes would also be same if they are at same temperature and pressure.

Since 14 L of each gas are taken, the oxygen will be the limiting reactant and ethane will be the excess reactant. Let's calculate the volume of ethane used:

14LO_2(\frac{2LC_2H_6}{7LO_2})

= 4LC_2H_6

From above calculations, 4 L of ethane are used. So, excess volume of ethane left after the completion of reaction = 14 L - 4 L = 10 L

Hence, 10 L of ethane will be remaining.

5 0
3 years ago
(a) 4.12 x 10^15 atoms U
DochEvi [55]

Answer:

1.63ₓ10⁻⁶ g of U

139.03 g of H

0.385 g of O

141.8 g of Pb

Explanation:

In first place, we need to convert the number of atoms to moles, as we know that 1 mol of anything occupies 6.02×10²³ particles

Therefore:

4.12×10¹⁵ atoms of U . 1 mol / 6.02×10²³ atoms = 6.84×10⁻⁹ moles of U

8.37×10²⁵ atoms of H . 1 mol /6.02×10²³ atoms = 139.03 moles of H

1.45×10²² atoms of O . 1 mol /6.02×10²³ atoms = 0.0241 moles of O

4.12×10²³ atoms of Pb . 1 mol /6.02×10²³ atoms = 0.684 moles of Pb

Moles . Molar mass = Mass (g)

6.84×10⁻⁹ moles of U . 238.03 g/mol = 1.63ₓ10⁻⁶ g of U

139.03 moles of H . 1 g/mol = 139.03 g of H

0.0241 moles of O . 16 g/mol = 0.385 g of O

0.684 moles of Pb . 207.2 g/mol = 141.8 g of Pb

8 0
3 years ago
Calculate the molarity (M) if 3.35g of H3PO4 is dissolved in water to give a total volume of 200mL
lyudmila [28]

Answer:

0.171 M

Explanation:

Step 1: Given data

  • Mass of H₃PO₄ (solute): 3.35 g
  • Volume of solution (V): 200 mL

Step 2: Calculate the moles of solute

The molar mass of H₃PO₄ is 97.99 g/mol.

3.35 g × 1 mol/97.99 g = 0.0342 mol

Step 3: Convert "V" to liters

We will use the conversion factor 1 L = 1000 mL.

200 mL × 1 L/1000 mL = 0.200 L

Step 4: Calculate the molarity of the solution

We will use the definition of molarity.

M = moles of solute / liters of solution

M = 0.0342 mol/0.200 L = 0.171 M

8 0
3 years ago
Is selenium tetrafluoride an ionic or covalent bond?
nasty-shy [4]

Answer:

Synthesis

The first reported synthesis of selenium tetrafluoride was by Paul Lebeau in 1907, who treated selenium with fluorine:[1]

Se + 2 F2 → SeF4

A synthesis involving more easily handled reagents entails the fluorination of selenium dioxide with sulfur tetrafluoride:[2]

SF4 + SeO2 → SeF4 + SO2

An intermediate in this reaction is seleninyl fluoride (SeOF2).

Other methods of preparation include fluorinating elemental selenium with chlorine trifluoride:

3 Se + 4 ClF3 → 3 SeF4 + 2 Cl2

Structure and bonding

Selenium in SeF4 has an oxidation state of +4. Its shape in the gaseous phase is similar to that of SF4, having a see-saw shape. VSEPR theory predicts a pseudo-trigonal pyramidal disposition of the five electron pairs around the selenium atom. The axial Se-F bonds are 177 pm with an F-Se-F bond angle of 169.2°. The two other fluorine atoms are attached by shorter bonds (168 pm), with an F-Se-F bond angle of 100.6°. In solution at low concentrations this monomeric structure predominates, but at higher concentrations evidence suggests weak association between SeF4 molecules leading to a distorted octahedral coordination around the selenium atom. In the solid the selenium center also has a distorted octahedral environment.

Reactions

In HF, SeF4 behaves as a weak base, weaker than sulfur tetrafluoride, SF4 (Kb= 2 X 10−2):

SeF4 + HF → SeF3+ + HF2−; (Kb = 4 X 10−4)

Ionic adducts containing the SeF3+ cation are formed with SbF5, AsF5, NbF5, TaF5, and BF3.[3] With caesium fluoride, CsF, the SeF5− anion is formed, which has a square pyramidal structure similar to the isoelectronic chlorine pentafluoride, ClF5 and bromine pentafluoride, BrF5.[4] With 1,1,3,3,5,5-hexamethylpiperidinium fluoride or 1,2-dimethylpropyltrimethylammonium fluoride, the SeF62− anion is formed. This has a distorted octahedral shape which contrasts to the regular octahedral shape of the analogous SeCl62−. [5]

Explanation:

4 0
3 years ago
Other questions:
  • An unknown quantity of sugar was completely dissolved in water at 75 degrees Celsius to form a clear and colorless solution. The
    13·1 answer
  • This is dimensional analysis-
    12·1 answer
  • What is the number of electrons in the outermost energy level of an oxygen atom
    15·2 answers
  • Which is responsible for the high thermal energy required to melt ice? (1 point)?
    5·1 answer
  • 11
    8·1 answer
  • What happen when the nitrate of an alkali metal is heatad?<br>​
    9·2 answers
  • What is the voltage required to push 0.5 amps of current through a 10 ohm resistor?
    14·1 answer
  • 8.5 g of rubidium are reacted completely with water.
    6·1 answer
  • Ca --&gt; CaO --&gt; CaCO3 --&gt; CO2
    13·1 answer
  • How would I Determine the number of moles in 3.51 x 10^23 formula units of CaCl2
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!